Answer:
n = 1.56 x 10¹⁷ electrons
Explanation:
First of all, we will calculate the current passing through wire:

where,
I = current = ?
q = charge = 9 mC = 0.009 C
t = time = 3.6 s
Therefore,

Now, for the same current in 10 s time the charge will be:
q = It = (0.0025 A)(10 s)
q = 0.025 C
Now, the number of electrons can be given as:

where,
n = no. of electrons = ?
q = charge = 0.025 C
e = charge on single electron = 1.6 x 10⁻¹⁹ C
Therefore,

<u>n = 1.56 x 10¹⁷ electrons</u>
Answer:
The wind spins blades of a wind turbine around a rotor, which spins a generator, which creates electricity (a generator converts mechanical energy into electricity).
Answer:
31.25 year .
Explanation:
The thickness of layer must change so the destructive interference may be converted into constructive interference . This can happen if thickness is reduced by λ /4 , so that path difference changes by 2 x λ /4 = λ /2 .
This will convert destructive to constructive interference.
change in thickness required = λ /4
= 525 / 4 nm
= 131.25 nm .
year required to wear off
= 131.25 / rate of decay
= 131.25 / 4.2
= 31.25 year .
Answer:
3.921*10^19 electrons
Explanation:
To find the number of electron that trough the car battery you first calculate the current by using the following formula, which relates the power with the voltage:
(1)
P: power of both headlights = 2(37.7W) = 75.4 W
I: current = ?
V: voltage of the battery = 12.0 V
You solve the equation (1) for I:

Next, you use the equivalence 1C = 6.241*10^18 electrons:

The number of electrons that cross the battery per second is 3.921*10^19 electrons