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4 years ago

Define the relationship between refraction and reflection

1 answer:

8 0

Reflection and refraction are two different phenomenons. In case of reflection, wave bounces back into the same medium after incident with the interface of two mediums. Reflection will happen if surface is shiny as well as smooth. If surface is irregular, one will get diffused reflection. Refraction means bending of light when waves travel from one medium to another

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A plastic tube allows a flow of 12.9 cm°/s of

VARVARA [1.3K]

Answer:

It will take $17.5968 s$ to fill a bottle with water.

Explanation:

Total capacity of tube $=227$ cm.

Rate of full up the water in the tube $=12.9 $\mathrm{cm}^{\circ} / \mathrm{s}$$

Total full up the tube $=$ rate $\times$ time

$T=r \times t$

$227 \mathrm{~cm}$$=12.9 \mathrm{~cm}^{\circ} / \mathrm{s} \times t$

$t=\frac{227}{12.9}$

$=17.5968s$

Learn more about seconds, refer :

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3 years ago

. The penalties for a person's second DUI conviction include completion of __________ hours of DUI school.

Kobotan [32]

The penalties for a person's second DUI conviction include completion of 21 hours of DUI school.

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3 years ago

When Esperanza describes people from outside of Mango Street as "Those Who Don't," she means that unlike her, they ______ .

Misha Larkins [42]

Answer:

As a child, Esperanza wants only to escape Mango Street. Her dreams of self-definition don't include the fact that she has any responsibility to her family or to the people around her, and she wishes to leave them all behind.

Explanation:

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2 years ago

Which type of radiation detection device uses a phosphor-coated surface to detect radiation?

labwork [276]

scintillation counter

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4 years ago

Read 2 more answers

The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘C is 2000 m/s. Note that 1.0 mol of diatomic hydrogen at

denis-greek [22]

Answer:

A) d. (1/4)(2000m/s) = 500 m/s

B) c. 4000 J

C) f. None of the above (2149.24 m/s)

Explanation:

The translational kinetic energy of a gas molecule is given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 1^-23 J/K

T = Absolute Temperature

but,

K.E = (1/2) mv²

where,

v = root mean square velocity

m = mass of one mole of a gas

Comparing both equations:

(3/2)KT = (1/2) mv²

v = √(3KT)/m _____ eqn (1)

FOR HYDROGEN:

v = √(3KT)/m = 2000 m/s _____ eqn (2)

FOR OXYGEN:

velocity of oxygen = √(3KT)/(mass of oxygen)

Here,

mass of 1 mole of oxygen = 16 m

velocity of oxygen = √(3KT)/(16 m)

velocity of oxygen = (1/4) √(3KT)/m

using eqn (2)

velocity of oxygen = (1/4)(2000 m/s) = 500 m/s

K.E = (3/2)KT

Since, the temperature is constant for both gases and K is also a constant. Therefore, the K.E of both the gases will remain same.

K.E of Oxygen = K.E of Hydrogen

K.E of Oxygen = 4000 J

using eqn (2)

At, T = 50°C = 323 k

v = √(3KT)/m = 2000 m/s

m = 3(1.38^-23 J/k)(323 k)/(2000 m/s)²

m = 3.343 x 10^-27 kg

So, now for this value of m and T = 100°C = 373 k

v = √(3)(1.38^-23 J/k)(373 k)/(3.343 x 10^-27 kg)

v = 2149.24 m/s

8 0

4 years ago