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Dmitry_Shevchenko [17]
3 years ago
5

A school bus weighing 1000 kg slows down from 15 m/s to a stop. What is the change in kinetic energy?

Physics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

They wishin' on me, yuh

I been movin' calm, don't start no trouble with me

Tryna keep it peaceful is a struggle for me

Don't pull up at 6 AM to cuddle with me

You know how I like it when you lovin' on me

I don't wanna die for them to miss me

Yes, I see the things that they wishin' on me

Hope I got some brothers that outlive me

They gon' tell the story, shYit was different with me

Explanation:

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Suppose that a block of mass 2 kg is pulled to the right with a force of 10 N, and the friction force on the block is directed t
Law Incorporation [45]

Answer:

The block has an acceleration of 3 m/s^{2}

Explanation:

By means of Newton's second law it can be determine the acceleration of the block.

\sum F_{r} = ma   (1)

Where \sum F_{r} represents the net force, m is the mass and a is the acceleration.

F_{x} + F{y} = ma  (2)

The forces present in x are F = 10 N and f = 4 N (the friction force):

F_{x} = 10 N - 4 N

Notice that f subtracts to F since it is at the opposite direction.

F_{x} = 6 N

The forces present in y balance each other:

F_{y} = 0

Therefore:

6 + 0 = ma  

6 N = (2kg)a  (3)

But 1 N = 1 Kg.m/s^{2} and writing (3) in terms of a it is get:

a = \frac{6 Kg.m/s^{2}}{2 Kg}  

a = 3 m/s^{2}

So the block has an acceleration of a = 3 m/s^{2}.

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3 years ago
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A beam of light bends when it passes from air into water, and then bends even more when it passes from water into glass. What ca
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Answer:

Certain Things Make Light Bend?

Explanation:

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4 0
2 years ago
The escape velocity is defined to be the minimum speed with which an object of mass m must move to escape from the gravitational
s344n2d4d5 [400]

Answer:

v = √2G M_{earth} / R

Explanation:

For this problem we use energy conservation, the energy initiated is potential and kinetic and the final energy is only potential (infinite r)

        Eo = K + U = ½ m1 v² - G m1 m2 / r1

        Ef = - G m1 m2 / r2

When the body is at a distance R> Re, for the furthest point (r2) let's call it Rinf

       Eo = Ef

       ½ m1v² - G m1 M_{earth} / R = - G m1 M_{earth} / R

      v² = 2G M_{earth} (1 / R - 1 / Rinf)

If we do Rinf = infinity     1 / Rinf = 0

       v = √2G M_{earth} / R

      Ef = = - G m1 m2 / R

The mechanical energy is conserved  

 

      Em = -G m1  M_{earth} / R

      Em = - G m1  M_{earth} / R

     R = int        ⇒  Em = 0

6 0
2 years ago
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