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2 years ago

A school bus weighing 1000 kg slows down from 15 m/s to a stop. What is the change in kinetic energy?

Physics

1 answer:

Mashutka [201]2 years ago

6 0

Answer:

They wishin' on me, yuh

I been movin' calm, don't start no trouble with me

Tryna keep it peaceful is a struggle for me

Don't pull up at 6 AM to cuddle with me

You know how I like it when you lovin' on me

I don't wanna die for them to miss me

Yes, I see the things that they wishin' on me

Hope I got some brothers that outlive me

They gon' tell the story, shYit was different with me

Explanation:

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The cardiovascular system consists of

guapka [62]

Consists of A. good luck

3 0

2 years ago

Two remote control cars with masses of 1.16 kilograms and 1.98 kilograms travel toward each other at speeds of 8.64 meters per s

Black_prince [1.1K]

The initial momentum of the system can be expressed as,

$p_i=m_1u_1+m_{2_{}}u_2$

The final momentum of the system can be given as,

$p_f=m_1v_1+m_{2_{}}v_2$

According to conservation of momentum,

$p_i=p_f$

Plug in the known expressions,

$\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_2v_2=m_1u_1+m_2u_2-m_1v_1 \\ v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2} \end{gathered}$

Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.

Plug in the known values,

$\begin{gathered} v_2=\frac{(1.16\text{ kg)(8.64 m/s)+(1.98 kg)(-3.34 m/s)-(1.16 kg)(-2.16 m/s)}}{1.98\text{ kg}} \\ =\frac{10.02\text{ kgm/s-}6.61\text{ kgm/s+}2.51\text{ kgm/s}}{1.98\text{ kg}} \\ =\frac{5.92\text{ kgm/s}}{1.98\text{ kg}} \\ \approx2.99\text{ m/s} \end{gathered}$

Thus, the final velocity of second mass is 2.99 m/s.

3 0

7 months ago

A mass weighting 16 lbs stretches a spring 3 inches. The mass is in a medium that exerts a viscous resistance of 20 lbs when the

const2013 [10]

Answer:

The equation for the object's displacement is $u(t)=0.583cos11.35t$

Explanation:

Given:

m = 16 lb

δ = 3 in

The stiffness is:

$k=\frac{m}{\delta } =\frac{16}{3} =5.33lb/in$

The angular speed is:

$w=\sqrt{\frac{k}{m} } =\sqrt{\frac{5.33*386.4}{16} } =11.35rad/s$

The damping force is:

$F_{D} =cu$

Where

FD = 20 lb

u = 4 ft/s = 48 in/s

Replacing:

$c=\frac{F_{D} }{u} =\frac{20}{48} =0.42lbs/in$

The critical damping is equal:

$c_{c} =\frac{2k}{w} =\frac{2*5.33}{11.35} =0.94lbs/in$

Like cc>c the system is undamped

The equilibrium expression is:

$u(t)=u(o)coswt+u'(o)sinwt\\u(o)=7=0.583\\u'(o)=0\\u(t)=0.583coswt\\u(t)=0.583cos11.35t$

3 0

2 years ago

1. What type of wave is sound? Does sound need a medium (substance) to travel through?

denpristay [2]

Answer:

1. What type of wave is sound?

2.Does sound need a medium to travel through?

3. What are the properties of sound waves?

Explanation:

1. The type of waves sound are is mechanical waves.

2. Sound needs a solid, liquid or gas (material medium) to travel through.

3. I believe they are wavelength, amplitude, frequency, time period and velocity.

I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

6 0

1 year ago

Sound travels slowest through gas because the atoms in a gas are further apart than the other states of matter.

Tanzania [10]

Answer:

false

Explanation:

If they were farther apart they would be able to slip by through which means that it can go by faster. If the atoms where closer together then yes they would be able to go by slower.

8 0

1 year ago