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slega [8]
3 years ago
10

Someone help me this please

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0
Think:  0.99x = 194 implies that x, the sample size, was 196.

The test was incorrect 2 times.  Look at "2" in the table and determine for yourself why.

Part C:  2/196 = 0.01  =>  1%
This makes sense, since 99% of the time the test is correct.

1% + 99% = 100%
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Cos y/ 1-sin y= 1+sin y/cos y. Verify the identity. Show All Steps!
Vlada [557]

Answer:

When proving identities, the answer is in the explanation.

Step-by-step explanation:

\frac{\cos(y)}{1-\sin(y)}

I have two terms in this denominator here.

I also know that 1-\sin^2(\theta)=\cos^2(theta) by Pythagorean Identity.  

So I don't know how comfortable you are with multiplying this denominator's conjugate on top and bottom here but that is exactly what I would do here.  There will be other problems will you have to do this.

\frac{\cos(y)}{1-\sin(y)} \cdot \frac{1+\sin(y)}{1+\sin(y)}

Big note here: When multiplying conjugates all you have to do is multiply fist and last.  You do not need to do the whole foil.  That is when you are multiplying something like (a-b)(a+b), the result is just a^2-b^2.

Let's do that here with our problem in the denominator.

\frac{\cos(y)}{1-\sin(y)} \cdot \frac{1+\sin(y)}{1+\sin(y)}

\frac{\cos(y)(1+\sin(y))}{(1-\sin(y))(1+\sin(y)}

\frac{\cos(y)(1+\sin(y))}{1^2-\sin^2(y)}

\frac{\cos(y)(1+\sin(y))}{1-\sin^2(y)}

\frac{\cos(y)(1+\sin(y))}{cos^2(y)}

In that last step, I apply the Pythagorean Identity I mentioned way above.

Now You have a factor of cos(y) on top and bottom, so you can cancel them out.  What we are really saying is that cos(y)/cos(y)=1.

\frac{1+\sin(y)}{cos(y)}

This is the desired result.

We are done.

6 0
3 years ago
What does f(5)means
Dima020 [189]

Answer: refresh

Step-by-step explanation:

4 0
3 years ago
Add or subtract. use the least common multiple as the denominator what is 5/8-5/25
Vinvika [58]

Answer:

17/40

Step-by-step explanation:

First let's find the least common denominator. The denominators are 8 and 25 so we need to find the least common multiple of 8 and 25.

8=2*2*2

25=5*5

Since they share no common factors the least common multiple of 8 and 25 is 8*25 which is 200.

Now we convert the fractions:

5/8*25/25=125/200

5/25*8/8=40/200

Then we subtract:

125/200-40/200=85/200

Now we simplify it:

17/40

8 0
3 years ago
Read 2 more answers
The value 5 is an upper bound for the zeros of the function shown below. f(x)=x^4+x^3 -11x^2-9x+18
Inessa [10]
Answer: True

Explanation:
According to the rational zeros theorem, if x=a is a zero of the function f(x), then f(a) = 0.

Given:  f(x) = x⁴ + x³ - 11x² - 9x + 18
From the calculator, obtain
f(5) = 448
f(4) = 126
f(3) = 0
f(2) = -20
f(1) = 0
f(0) = 18
f(-1) = 16
f(-2) = 0
f(-3) = 0

The polynomial is of degree 4, so it has at most 4 real zeros.
From the calculations, we found all 4 zeros as x = -3, -2, 1, and 3.
Therefore
f(x) = (x+3)(x+2)(x-1)(x-3).

For x>3, f(x)increases rapidly. Therefore there are no zeros for x>3.
The statement that x=5 is an upper bound for the zeros of f(x) is true.



7 0
4 years ago
Read 2 more answers
Rewrite in y=mx+b form and show ur work 2x+y=3x-7
Alenkasestr [34]
It would be y=x-7 just minus 2x on both sides and you get y=x-7

7 0
3 years ago
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