Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
I believe the answer is B. 42 + x = 90
Hello friend,here is the sum
0.3+0.4= 0.7
0.3²+0.4²=0.9+0.16=0.25
<span>Hope helped !</span>
The answer is 4x+28 it was pretty simple you just had to add up all the sides
Answer:
x^2 +2x -5
Step-by-step explanation:
f(x) = 2x+3
g(x) = x^2 -8
f(x)+g(x) = 2x+3+ x^2 -8
Combine like terms
= x^2 +2x -5