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fenix001 [56]
4 years ago
6

What is the range for this data set?37 years9 years41 years​

Mathematics
1 answer:
rewona [7]4 years ago
6 0

Answer:

30 years

Step-by-step explanation:

41 minus 11=

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1. The sum of the three consecutive members of the geometric sequence is 13. The proportion of the third and the first member is
aev [14]
If a = first term and r = common ratio we have

a + ar + ar^2 = 13   and ar^2 / a = r^2 = 9

so r = 3

and a + 3a + 9a = 13 
so a = 1

so they are  1,3 and 9 

2.
in geometric series we have

4 , 4r ,4r^2 , 60

Arithmetic;
 4,  4r , 4r + d ,  4r + 2d

so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30 
so d = 30 - 2r 
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0

2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r  = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24

and the numbers are 4*3 =  12 , 4*3^2 = 36

first 3  are  4 , 12 and 36  ( in geometric)
and last 3 are 12, 36 and 60  ( in arithmetic)

The 2 numbers we ause are 12 and 36.





7 0
3 years ago
Manuel bought x x movie tickets for $6.50 each and y y bags of popcorn for $2.50 each. write an algebraic expression for the tot
Alekssandra [29.7K]
6.50x+2.50y = total 
with x = # of movie tickets 
with y= # of bags of popcorn
5 0
4 years ago
If a(x) = 3x + 1 and b(x)= squareroot x-4, what is the domain of (b*a)(x)?
oksano4ka [1.4K]

\boxed{ \ x \geq 1 \ } or can be written as \boxed{ \ [1, \infty) \ }

<h3>Further explanation</h3>

This is a question about the composition of functions and how to get a domain function.

Given \boxed{ \ a(x) = 3x + 1 \ } and \boxed{ \ b(x) = \sqrt{x - 4} \ }.

We will form (b o a)(x) and then determine the domain.

<u>Step-1</u>

\boxed{ \ (b \circ a)(x) = b(a(x)) \ }

Replace each appearance of x in b(x) with \boxed{ \ a(x) = 3x + 1 \ }.

\boxed{ \ (b \circ a)(x) = \sqrt{(3x + 1) - 4} \ }

Thus, \boxed{ \ (b \circ a)(x) = \sqrt{3x - 3} \ }

<u>Step-2</u>

To be defined, the value under the radical sign must not be negative. Therefore, the domain of (b \circ a)(x) = \sqrt{3x - 3} are processed as follows.

\boxed{ \ 3x - 3 \geq 0 \ }

Both sides added by 3.

\boxed{ \ 3x \geq 3 \ }

Both sides divided by 3.

\boxed{ \ x\geq 1 \ }

Thus, the domain of (b \circ a)(x) = \sqrt{3x - 3} is \boxed{ \ x \geq 1 \ } or can be written as \boxed{ \ [1, \infty) \ }

<h3>Learn more</h3>
  1. If f(x) = x² – 2x and g(x) = 6x + 4, for which value of x does (f o g)(x) = 0? brainly.com/question/1774827
  2. Solve for the value of the function composition brainly.com/question/2142762
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Keywords: composition of function, if a(x) = 3x + 1, and, b(x) = √(x-4), what is the domain of, (b o a)(x), b(a(x)), defined, the value, under the radical sign, must not be negative,

4 0
4 years ago
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The graph of y=3x+2x-2^2 is shown. A) what are the coordinates
lukranit [14]

Answer:

(

2

,

8

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Explanation:

Two lines are parallel if they share the same slope.

Any line parallel to

y

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Now, we have:

y

=

3

x

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−

2

x

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d

y

d

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d

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(

y

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=

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Step-by-step explanation:

7 0
2 years ago
Find the inequality represented by the graph
bezimeni [28]
The answer is y ≥ 1/2x
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