Question

(n-3)(n-5)what's the equivalent

Answer 1

Lets expand the expression using the FOIL method
FOIL=First,Outer,Inner,Last

We'd start by multiplying the first numbers in each parenthesis by eachother:

(n-3)(n-5)
n*n=n²

Now the outer two values...

(n-3)(n-5)
-5n

The inner two values

(n-3)(n-5)
-3n

And the last two values
(n-3)(n-5)
-3*-5=15

Now just put all of the expressions together...

n²-5n-3n+15
simplify
n²-8n+15

Answer=n²-8n+15