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Klio2033 [76]
2 years ago
8

Help with this plz.Solve the system of equations using the elimination method.​

Mathematics
2 answers:
forsale [732]2 years ago
5 0

Let's solve your system by elimination.

8x+y=−16;3x−y=5

8x+y=−16

3x−y=5

Add these equations to eliminate y:

11x=−11

Then solve: 11x=−11 for x:

11x=−11

11x

11

=

−11

11

(Divide both sides by 11)

x=−1

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

8x+y=−16

Substitute: −1 for x in 8x+y=−16:

(8)(−1)+y=−16

y−8=−16(Simplify both sides of the equation)

y−8+8=−16+8(Add 8 to both sides)

y=−8

Answer:

x=−1 and y=−8

dimaraw [331]2 years ago
3 0

Answer:Multiply each equation by a suitable number so that the two equations have the same leading coefficient.

Subtract the second equation from the first.

Solve this new equation for y.

Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.

Step-by-step explanation:

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For a=3-5c when c=-0.5, what does a equal?
Sonbull [250]

Plug in -0.5 for c


a = 3 - 5(-0.5)


Multiply -5 with (-0.5)


a = 3 + 2.5


Simplify


a = 5.5


a = 5.5 is your answer


hope this helps

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100%....300<br>35% .... X​
Lady bird [3.3K]

Answer:

x = 105

Step-by-step explanation:

100\% = 300 \\  \frac{100}{100}  =  \frac{300}{100}  \\ 1\% = 3 \\ 35\% = 3 \times 35 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 105

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3 years ago
Please help and good night​
lana66690 [7]

Answer:

(7) n = ⁴/₃

(8) x = -5

(9) d = ³/₂

(10) v = -20

Step-by-step explanation:

(7) n-\frac{8}{9} = \frac{4}{9}

n-\frac{8}{9} = \frac{4}{9} \\\\Collect \ similar \ terms \ together\\\\n = \frac{4}{9} + \frac{8}{9} \\\\n = \frac{4+8}{9} \\\\n = \frac{12}{9} \\\\n = \frac{4}{3}

(8)

\frac{3}{2} + \ x = -\frac{7}{2}\\\\collect \ similar \ terms \ together\\\\x = -\frac{7}{2}  -\frac{3}{2} \\\\x = \frac{-7-3}{2} \\\\x = \frac{-10}{2} \\\\x = -5

(9)

\frac{6}{5} = \frac{d}{(\frac{5}{4} )} \\\\cross \ and \ multiply\\\\5d = 6(\frac{5}{4} )\\\\5d = \frac{30}{4} \\\\d = \frac{30}{4\times 5} \\\\d = \frac{30}{20} \\\\d = \frac{3}{2} \\\\d = 1\frac{1}{2}

(10)

-\frac{1}{8} v = \frac{5}{2} \\\\\frac{-v}{8} = \frac{5}{2} \\\\cross \ and \ multiply\\\\-2v = 40\\\\-v = \frac{40}{2} \\\\-v = 20\\\\v = -20

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