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professor190 [17]
3 years ago
12

Seven more than twice a number is 1

Mathematics
2 answers:
Ulleksa [173]3 years ago
7 0

Answer:

2x+7=1

2x=1-7

2x=-6

2x/2=-6/2

x=-3

Brainliest Helps a lot.

IRINA_888 [86]3 years ago
5 0

Answer:

Step-by-step explanation:

I think that’s wrong it’s 14

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Put 5x – 6y = 12 in slope intercept form
Ede4ka [16]

Answer:

  y = 5/6x -2

Step-by-step explanation:

Subtract 5x and divide by -6:

  -6y = -5x +12 . . . .subtract 5x

  y = 5/6x -2 . . . . . divide by -6

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How do i know if the "y = " is additon or subtraction?
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2x+4y=16
2x+4(4)=16
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Solve the Anti derivative.​
Alex Ar [27]

Answer:

\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C

General Formulas and Concepts:

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]:                                                                \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Trig Integration:                                                                                                           \displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx<u />

<u />

<u>Step 2: Integrate Pt. 1</u>

  1. [Integral] Factor fraction denominator:                                                         \displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx
  2. [Integral] Integration Property - Multiplied Constant:                                   \displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx

<u>Step 3: Identify Variables</u>

<em>Set up u-substitution for the arctan trig integration.</em>

\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx

<u>Step 4: Integrate Pt. 2</u>

  1. [Integral] Substitute u-du:                                                                               \displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du
  2. [Integral] Trig Integration:                                                                               \displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C
  3. [Integral] Simplify:                                                                                           \displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C
  4. [integral] Multiply:                                                                                           \displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C
  5. [Integral] Back-Substitute:                                                                             \displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0
2 years ago
Finding Distances from the Mean
jarptica [38.1K]

Answer:

x = 0.3, y = 5.3, z = 17.3

Step-by-step explanation:

Since given question is incomplete, so here is the complete table for the distance from the mean.

Temp (°F)                              29      38       45    31      50     58     62    

Distance from the mean    15.7    6.7       x    13.7      y     13.3       z

It's given that the mean of the data is 44.7

Since distance from the mean of a data is the absolute value of the difference of data and mean,

Therefore, distance from the mean of the data will be,

x = |44.7 - 45| = 0.3 (absolute value of the difference)

y = |44.7 - 50| = 5.3

z = |44.7 - 62| = 17.3

6 0
3 years ago
Point <img src="https://tex.z-dn.net/?f=P%5E1" id="TexFormula1" title="P^1" alt="P^1" align="absmiddle" class="latex-formula"> i
lawyer [7]

Answer:

(0, -1)

Step-by-step explanation:

(x, y) → (x - 6, y - 1)

Apply the rule to point 'P'.

(6,0)\rightarrow(6-6,0-1)\rightarrow\boxed{(0,-1)}

Hope this helps.

6 0
3 years ago
Read 2 more answers
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