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andrey2020 [161]
3 years ago
10

a triangular prism and two nets are shown: a right triangular prism is shown with two nets. the triangular base of the prism has

height 5 inches, base 12 inches, and hypotenuse 13 inches. the length of the prism is 15 inches. net a has 3 rectangles having dimensions 5 by 15, 15 by 12, and 15 by 13, and two triangles having legs 5 inches and 12 inches. net b has 3 rectangles having dimensions 5 by 13, 13 by 12, and 13 by 15, and two triangles having legs 5 inches and 12 inches. which is the correct net of the prism and what is the surface area of the prism?
Mathematics
2 answers:
aleksandrvk [35]3 years ago
8 0
Net for the prism will have 3 rectangles with dimensions 5 by 15, 12 by 15 and 13 by 15 and 2 triangles with legs 5 inches and 12 inches.
The correct net is net a.

Surface area = sum of areas of the three rectangles and sum of the two triangles.
SA = (5 x 15) + (12 x 15) + (13 x 15) + (5 x 12) = 75 + 180 + 195 + 60 = 510 square inches.
mariarad [96]3 years ago
7 0

Answer:

510 square inches.

Step-by-step explanation:

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4. An automobile dealership received 11 cars that needed to be detailed. If the
vova2212 [387]

Answer:

11 cars =21/2 hours

Convert 21/2 hours to minutes

60minutes =1hour

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11cars=150 mins

1 car =1/11×150mins=

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Step-by-step explanation:

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3 years ago
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Crazy boy [7]

Answer:

2:6=2/6=1/3=1:3

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Step-by-step explanation:

3 0
3 years ago
The number of fish in a small bay is modeled by the function F defined by F(t)=10 (t3 â 12t2 + 45t +100), where t is measured in
RSB [31]

The graph of the given function is attached showing characteristics of the function.

The correct responses are;

  • (a) F'(4) = -30 means that <u>on day 4, the number of fish in the bay is decreasing at a rate of 30 fish per day</u>.
  • (b) Over the interval 0 ≤ t ≤ 8 the absolute minimum number of fish in the bay is;<u> 1,000</u>.
  • (c) The values of <em>t</em> at which the rate of change is decreasing is; <u>3 ≤ t ≤ 8</u>
  • (d) The rate of change of the number of pelicans flying near is; P' =  <u>10·(3·c² - 24·c  + 45)</u>

Reasons:

The given function is; f(t) = 10·(t³ - 12·t² + 45·t + 100)

Where;

t = Number of days

0 ≤ t ≤ 8

(a) The derivative of the given function is presented as follows;

F'(t) = 10 × (3·t² - 2×12·t + 45) = 10·(3·t² - 24·t  + 45)

Therefore;

F'(4) = 10 × (3 × 4² - 24 × 4  + 45) = -30

Therefore F'(4) = -30 means that on day 4, the <u>number of fish in the bay is decreasing at 30 fish per day</u>.

(b) The absolute minimum is given as follows;

At a minimum or maximum value, F'(t) = 10·(3·t² - 24·t  + 45) = 0

Which gives;

3·(t - 5)·(t - 3) = 0

t = 5, or t = 3

At t = 5, we have;

f(5) = 10 × (5³ - 12 × 5² + 45 × 5 + 100) = 1,500

At t = 3, we have;

f(3) = 10 × (3³ - 12 × 3² + 45 × 3 + 100) = 1,540

Therefore, f(5) = 1,500 is a local maximum

However, at x = 0, we have;

f(0) = 10 × (0³ - 12 × 0² + 45 × 0 + 100) = 1000

At x = 8, we have;

f(8) = 10 × (8³ - 12 × 8² + 45 × 8 + 100) = 2,040

Therefore, the absolute minimum is given at t = 8, where f(t) = <u>1,000</u>

(c) The values of <em>t</em> at which the rate of change in the number of fish in the

bay is decreasing is between the local maximum at t = 3, and the local

minimum at t = 5, which gives;

The rate of change of the number of fish is decreasing for values of t in the range;

  • <u>3 ≤ t ≤ 5</u>

(d)  P = 10·(t³ - 12·t² + 45·t + 100)

P' =  10·(3·t² - 24·t  + 45)

At time t = c, we have;

  • P' =  10·(3·c² - 24·c  + 45)

<em>Based on a similar question online, we have;</em>

<em>(c) The interval over which the rate of change is decreasing</em>

<em>(d) The rate of change of the number of pelicans flying near the bay at t = c</em>

Learn more about differentiation of functions here:

brainly.com/question/1422315

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2 years ago
If x = -1 then how much is 2x - 1
Elan Coil [88]

Answer: -3

Step-by-step explanation: 2x = -2 then you subtract 1 from that which is the same as adding negative one so -2 - 1 or -2 + -1 = -3

6 0
4 years ago
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