Question

A bag contains tiles number 1-10. What is the probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3?​

Answer 1

Answer:

0.12 = 12% probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of independent events:

Suppose we have two events, A and B, that are independent. The probability of both happening is given by:

$P(A \cap B) = P(A) \times P(B)$

In this question:

Event A: Selecting a prime number.

Event B: Selecting a number less than or equal to 3

Probability of selecting a prime number:

Between 1 and 10, we have 4 prime numbers(2,3, 5 and 7), out of 10. So

$P(A) = \frac{4}{10}$

Probability of selecting a number less than or equal to 3:

Three numbers(1,2,3) out of 10. So

$P(B) = \frac{3}{10}$

Probability of both:

$P(A \cap B) = P(A) \times P(B) = \frac{4}{10} \times \frac{3}{10} = \frac{12}{100} = 0.12$

0.12 = 12% probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3