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stich3 [128]
3 years ago
7

What is the range of the function on the graph?

Mathematics
2 answers:
Marta_Voda [28]3 years ago
3 0

Answer:

no. 4

Step-by-step explanation:

the numbers start at two and keeps going up.

Svet_ta [14]3 years ago
3 0
<h2>Answer:</h2>

The range of the function on the graph is:

    4. all real numbers greater than or equal to 2.

<h2>Step-by-step explanation:</h2>

Domain of a function--

A domain of a function is the set of all the x-values i.e. the value of the independent variable for which a function is defined.

Range of a function--

The range of a function are the set of all the values attained by a function.

By looking at the function we observe that the function is defined for all x≥1.

and the function attains all the values greater than or equal to 2.

This means that domain of the function = x≥1

and range of the function =  all real numbers greater than or equal to 2

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mixer [17]

Answer:

\frac{5+-\sqrt{53} }{2}

Step-by-step explanation:

in the equation given these are the values:

a=1   b= -5     c= -7

if we plug this in the quadratic formula \frac{-(-5)+-\sqrt{(-5)^2-4(1)(-7)} }{2(1)}

this is simplified to \frac{5+-\sqrt{53} }{2}

hope this helped

3 0
3 years ago
1.)David is starting a collection of baseball cards. He currently has 16 cards in his collection. He hopes to buy 5 more each mo
Elena-2011 [213]
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6 0
4 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
Which of the following is the best estimate of the circumference of a circle that has a diameter of 7 feet? 42 ft 21 ft 14 ft 11
11Alexandr11 [23.1K]

Answer:

21 ft

Step-by-step explanation:

Hope it helps

3 0
2 years ago
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