Question

during the 2009-2010 basketball season, the number of points scored in each game by the boston celtics was approximately normally distributed with a mean of 99.2 points and a standard deviation of 10.5 pthe mean number of points scored by los angeles lakers was 101.7. in what proportion of their games did the celtics score more than the lakers' mean score?

Answer 1

To solve this problem, we use the z statistic.  The z formula is:

z = (x – u) / s

where x is lakers score = 101.7, u is Celtics score = 99.2, s is standard dev = 10.5

z = (101.7 – 99.2) / 10.5 = 0.24

 

using the normal distribution table at z = 0.24, the P value is:

P (z = 0.24) = 0.5984 = 59.84%