(2/3)-j
put it in parenthesis, the 2/3 to solve it correctly.
The answer is A = 2x² + 6x - 20
The area of the rectangle is:
A = l * w
l = x + 5
w = 2x - 4
A = (x + 5)(2x - 4)
Use the distributive property to calculate this:
A = (x + 5)(2x - 4)
A = x * 2x + x * (-4) + 5 * 2x + 5 * (-4)
A = 2x² - 4x + 10x - 20
A = 2x² + 6x - 20
Answer:
x=-1 is a maximum vaue.
Step-by-step explanation:
To find the minimum and maximum values of the function f(x), we're going to derivate it:
f(x) = –5x^2 – 10x + 6 ⇒ f'(x) = -10x - 10
The points where f'(x) is zero, could be a maximum or a minimum. Then:
f'(x) = -10x - 10 = 0 ⇒ x=-1
Now, to know if x=-1 is a maximum or a minimum, we need to evaluate the original function for x when it tends to -1 from the right and from the left.
Therefore:
For x=-2:
f(x) = 6 (Positive)
For x=0:
f(x) = 6 (Positive)
For x=-1
f(x) = 11 (Positive)
Given that at x=-1, f(x) = 11, and then it goes down to 6 when x=0, we can say that it's a maximum.
We need to 'standardise' the value of X = 14.4 by first calculating the z-score then look up on the z-table for the p-value (which is the probability)
The formula for z-score:
z = (X-μ) ÷ σ
Where
X = 14.4
μ = the average mean = 18
σ = the standard deviation = 1.2
Substitute these value into the formula
z-score = (14.4 - 18) ÷ 1..2 = -3
We are looking to find P(Z < -3)
The table attached conveniently gives us the value of P(Z < -3) but if you only have the table that read p-value to the left of positive z, then the trick is to do:
1 - P(Z<3)
From the table
P(Z < -3) = 0.0013
The probability of the runners have times less than 14.4 secs is 0.0013 = 0.13%
C. 42.39 times 0.1 is 4.239. 42.39-4.239= 38.151 which rounds to 38.15