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3 years ago

How to divide 246 divided by 6?

1 answer:

4 0

Well you see how may times 6 can go into 24. Once you figure that out you put your number on the top. Then you subtract 24 from 24, once you get that you bring down your remaining number which is 6. Then you see how many times 6 can go into 6, when you get that you put it at the top.

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The temperature of a certain solution is estimated by taking a large number of independent measurements and averaging them. The

Mademuasel [1]

Answer:

(a) The 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b) The confidence level is 68%.

(d) The 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

Step-by-step explanation:

Let X = temperature of a certain solution.

The estimated mean temperature is, $\bar x=37^{o}C$ .

The estimated standard deviation is, $s=0.1^{o}C$ .

(a)

The general form of a (1 - α)% confidence interval is:

$CI=SS\pm CV\times SD$

Here,

SS = sample statistic

CV = critical value

SD = standard deviation

It is provided that a large number of independent measurements are taken to estimate the mean and standard deviation.

Since the sample size is large use a z-confidence interval.

The critical value of z for 95% confidence interval is:

$z_{0.025}=1.96$

Compute the confidence interval as follows:

$CI=SS\pm CV\times SD\\=37\pm 1.96\times 0.1\\=37\pm0.196\\=(36.804, 37.196)\\\approx (36.80^{o}C, 37.20^{o}C)$

Thus, the 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b)

The confidence interval is, 37 ± 0.1°C.

Comparing the confidence interval with the general form:

$37\pm 0.1=SS\pm CV\times SD$

The critical value is,

CV = 1

Compute the value of P (-1 < Z < 1) as follows:

$P(-1$

The percentage of z-distribution between -1 and 1 is, 68%.

Thus, the confidence level is 68%.

(c)

The confidence interval for population mean can be constructed using either the z-interval or t-interval.

If the sample selected is small and the standard deviation is estimated from the sample, then a t-interval will be used to construct the confidence interval.

But this will be possible only if we assume that the population from which the sample is selected is Normally distributed.

Thus, the necessary assumption is that the population is normally distributed.

(d)

For n = 10 compute a 95% confidence interval for the temperature as follows:

The (1 - α)% t-confidence interval is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

The critical value of t is:

$t_{\alpha/2, (n-1)}=t_{0.025, 9}=2.262$

*Use a t-table for the critical value.

The 95% confidence interval is:

$CI=37\pm 2.262\times \frac{0.1}{\sqrt{10}}\\=37\pm 0.072\\=(36.928, 37.072)\\\approx (36.93^{o}C, 37.07^{o}C)$

Thus, the 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

3 0

3 years ago

Solve the inequality.

borishaifa [10]

2>8-4h/3 subtract 8 from both sides

-6>-4h/3 multiply both sides by 3

-18>-4h divide both sides by -4 (and reverse sign because of division by a negative value)

4.5<h or by convention...

h>4.5

8 0

3 years ago

How do I solve this please?

djyliett [7]

Answer:

given us,

n=4

here

3^-n+1-3^-n+2

3^-4+1-3^-4+2

-4+1-4+2

-5

Step-by-step explanation:

we can put value in n .we can power add and subtract then we can cut 3 then power we can add or subtract

7 0

3 years ago

What is the radius pf a circle whose equation is (x+5)^2+(y-3)^2=4^2

Lerok [7]

Answer:

we know that

the equation of the circle is of the form

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center of the circle

r is the radius of the circle

in this problem we have

(x+5)^2+(y-k)^2=r^2

the center is the point (-5,3)

the radius is 4 units

therefore

the answer is

The radius of the circle is equal to 4 units

4 0

3 years ago

Read 2 more answers

Find the quotient of 2.6 divided by 0.04

lara31 [8.8K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers