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3 years ago

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Mathematics

1 answer:

victus00 [196]3 years ago

3 0

Answer:

the answer will be table -1

Step-by-step explanation:

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Write two numbers that multiply to the value on top and add to the value on bottom.

zavuch27 [327]

2 and 4 because they all multiply and add up to 12 and 20

4 0

3 years ago

Read 2 more answers

What is the amplitude of the function?

Licemer1 [7]

Answer:

Step-by-step explanation:

Take the absolute value of the lowest y value.

$| - 1| = 1$

Take the absolute value of highest y value.

$|3| = 3$

Add those two together and divide by two.

$\frac{1 + 3}{2} = 2$

So the amplitude is 2

5 0

2 years ago

WZ and XR are diameters of circle C. The diagram is not drawn to scale. What is the measure of ZWX?

Inessa05 [86]

Answer:

Measure of arc ZWX is <u>230°.</u>

Step-by-step explanation:

Given:

arc WX = 50°

Now

The diameter divide a circle into two equal parts

$arc\ ZWX=arc\ ZRW+arc\ WX$

Since WZ is diameter of the circle.

$arc\ ZRW=180\°$

substituting in above equation we get

$arc\ ZWX=180\°+50\°=230\°$

Hence Measure of arc ZWX is <u>230°.</u>

7 0

3 years ago

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

How to simplify 6 +8b^2 +3b -6 - 10b^2

kozerog [31]

Answer:

-2b^2+3b

Step-by-step explanation:

You just have to add like terms, which is the single numbers, the numbers with just the variables, and the numbers with variables that are squared.

5 0

3 years ago