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3 years ago

What is the rate of change of the function y = 2x-3y=2x−3?

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

The Correct Answer = 3

Step-by-step explanation:

The average rate of change it is the change on y of the two points over the change in x

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− 4 /5 + 40/75 +100%

Reika [66]

Answer:

0.266666666

Step-by-step explanation:

7 0

2 years ago

Consider the following geometric series. [infinity] (−7)n − 1 8n n = 1. Find the common ratio. Determine whether the geometric s

Hatshy [7]

Answer:

d67d6d 34r2

Step-by-step explanation:

d53eududc6ttd5cf

3 0

3 years ago

charity is four times as old as her daughter. she is also six years younger than her husband. The sum of their ages ten years to

Pachacha [2.7K]

Answer:

36years

Step-by-step explanation:

Let charity present age be x

Charity daughter present age be y

Charity husband present age be z

If the sum of their ages ten years to come is 117, then;

10+x+10+y+10+z = 117

30+x+y+z = 117

x+y+z = 87 ... 1

If charity is four times as old as her daughter, then;

x = 4y

y = x/4 ... 2

If she is also six years younger than her husband, then;

x = z- 6

z = x+6 .. 3

Substitute 2 and 3 into 1;

x + x/4 + (x+6) = 87

Multiply through by 4

4x + x + 4(x+6) = 4(87)

5x+4x+24 = 348

9x = 348 - 24

9x = 324

x = 324/9

x = 36

hence Charity is 36years old today

5 0

3 years ago

10lb bag of potatoes or $5.50 or 15lb bag of potatoes for $8.40 which is a better deal

Jobisdone [24]

15lbs is a better deal

6 0

3 years ago

Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and

Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling:

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437$

P(sample average sediment density is at most 3.00)

$P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)$

Calculation the value from standard normal z table, we have,

$P(x \leq 3.00) = 0.918$

0.918 is the probability that the sample average sediment density is at most 3.00

4 0

3 years ago