As it is shown in the figure, the length of the square's side s is also the length of the circle's diameter d:
s = d = 28 in.
• Computing the area of the square:
A₁ = s²
A₁ = 28²
A₁ = 28 × 28
A₁ = 784 in² ✔
• Computing the area of the circle:
A₂ = π × r²
A₂ = π × (d/2)²
A₂ = π × (28/2)²
A₂ = π × 14²
A₂ ≈ 3.14 × 14 × 14
A₂ ≈ 615.44 in² ✔
—————
• The area of the shaded portion is equal to the difference between the area of the square and the area of circle:
A = A₁ – A₂
A ≈ 784 – 615.44
A ≈ 168.56 in² <——— this is the answer (1st option).
I hope this helps. =)
Answer:
c. m∠1 + m∠6 = m∠4 + m∠6
Step-by-step explanation:
Given: The lines l and m are parallel lines.
The parallel lines cut two transverse lines. Here we can use the properties of transverse and find the incorrect statements.
a. m∠1 + m∠2 = m∠3 + m∠4
Here m∠1 and m∠2 are supplementary angles add upto 180 degrees.
m∠3 and m∠4 are supplementary angles add upto 180 degrees.
Therefore, the statement is true.
b. m∠1 + m∠5 = m∠3 + m∠4
m∠1 + m∠5 = 180 same side of the adjacent angles.
m∠3 + m∠4 = 180, supplementary angles add upto 180 degrees.
Therefore, the statement is true.
Now let's check c.
m∠1 + m∠6 = m∠4 + m∠6
We can cancel out m∠6, we get
m∠1 = m∠4 which is not true
Now let's check d.
m∠3 + m∠4 = m∠7 + m∠4
We can cancel out m∠4, we get
m∠3 = m∠7, alternative interior angles are equal.
It is true.
Therefore, answer is c. m∠1 + m∠6 = m∠4 + m∠6
Answer:
That you answer
Step-by-step explanation:
Given 3x - 2 <2x +1 3x -2x 1 + 2 x <3 or x∈(−∞,3)
The lines y=3x−2 and y=2x+1 both will intersect at x=3
Clearly, the dark line shows the solution of 3x−2<2x+1.
