The absolute value of a number is its distance away from zero. Depending on how far away a number is, it has a less or greater absolute value. (-2,-2) have the same absolute value while (-2,5) have a different absolute value. Which has a greater absolute value? -25 or 6? The answer: -25, it is farther away from zero.

6 0

3 years ago

the probability of drawing a red coin after three red coins are put back in the bag to replace the blue one that has been remove

Wewaii [24]

4? I'm not sure. Just guessed.

3 0

3 years ago

Each of three coins has two sides, heads and tails. Represent the heads or tails status of each coin by a logical variable (A fo

jeka94

Answer:

(a) F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

Step-by-step explanation:

(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either

A is heads and the others are tails (AB'C')

B is heads and the others are tails (A'BC')

C is heads and the others are tails (A'B'C)

Hence, as a minterm expansion,

F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) To get the corresponding maxterm expansion, we convert to binary.

$F(A, B, C) = \sum (100, 010, 001) = \sum(4,2,1)$

The maxterm is the product of the complements.

$F(A, B, C) = \prod (0, 3, 5, 6, 7) = \prod(000, 011, 101, 110, 111)$

Expanding,

F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

3 0

3 years ago