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Anarel [89]
3 years ago
15

Name of the geometric solid suggested by a number cube

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0
I think its d.... but dont listen to me.<span>
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Schoolyard has an area of 3,564ft.² the section that is in the shape of a triangle is just for picnic table and what is the area
asambeis [7]

Answer:

The area of the section for the picnic tables is 1,188\ ft^{2}

Step-by-step explanation:

we know that

The area of the schoolyard is equal to the area of a rectangle plus the area of a triangle

so

3,564=44*(2x-x)+\frac{1}{2}(2x-x)*44\\ \\3,564=44x+22x\\\\3,564= 66x\\ \\x=54\ ft

The area of the triangle is equal to

22x=22*54=1,188\ ft^{2}

6 0
3 years ago
Please help! I was absent!
lesya692 [45]
I got 6.3 not sure if Im right
7 0
3 years ago
Solve for
faust18 [17]

Given equation : n(17+x)=34x−r.

We need to solve it for x.

Distributing n over (17+x) on left side, we get

17n + nx  = 34x - r.

Adding r on both sides, we get

17n+r + nx  = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

17n + r + nx-nx = 34x-nx

17n + r = 34x -nx.

Factoring out gcf x on right side, we get

17x + r = x(34-n).

Dividing both sides by (34-n), we get

\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}

\frac{(17x + r)}{(34-n)} = x

<h3>Therefore, final answer is x=\frac{(17x + r)}{(34-n)}.</h3>
7 0
3 years ago
Read 2 more answers
A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
Whats 3 divided by 612
Novay_Z [31]
3 divided by 612=0.00490196
4 0
2 years ago
Read 2 more answers
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