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2 years ago

Given the function f(x) = 5x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

1 answer:

3 0

$f(x)=5x\\\frac{f(1)-f(0)}{1-0}\\\frac{5-0}{1}\\5\\\\\frac{f(3)-f(2)}{3-2}\\\frac{15-10}{1}\\5$

A: 5; 5

B: 1; they are the same

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Ethan sold 2 3 gallon of lemonade. Kayla sold some lemonade too. Together, they sold 1 1 4 gallons. Who sold more lemonade, Etha

zhenek [66]

Step-by-step explanation:

Ethan sold 2/3 gallon of lemonade.

Kayla sold some lemonade too.

Together they sold 1 1/4 gallons.

Subtract 2/3 from 1 1/4 as follows :

$S=1\dfrac{1}{4}-\dfrac{2}{3}\\\\=\dfrac{5}{4}-\dfrac{2}{3}\\\\=\dfrac{7}{12}$

So, Kayla sold 7/12 gallons of lemonade.

As 2/3 is more than 7/12, it means Ethan sold more lemonade.

$\dfrac{2}{3}-\dfrac{7}{12}=\dfrac{1}{12}$

It means Eathn sold 1/12 more lemonade.

5 0

3 years ago

Given: m∠EYL=72° Find: mEHL , mLVE

White raven [17]

Answer:

Part 1) The measure of arc EHL is $108\°$

Part 2) The measure of angle LVE is $54\°$

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$m$

we have

$m$

substitute

$72\°=\frac{1}{2}(y-x)$

$144\°=(y-x)$

$y=144\°+x$ ------> equation A

Remember that

$x+y=360\°$ -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

$x+(144\°+x)=360\°$

$2x=360\°-144\°$

$x=216\°/2=108\°$

Find the value of y

$y=144\°+x$

$y=144\°+108\°=252\°$

therefore

The measure of arc EHL is $108\°$

The measure of arc EVL is $252\°$

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

$m$

we have

$x=108\°$

substitute

$m$

3 0

2 years ago

1. Write out the law of cosines and find the hypotenuse of triangle with 2 sides lengths equal to three and the included angle m

LUCKY_DIMON [66]

Answer:

1.) $\sqrt{13.341}$ ≈ 3.652

2.) I would say something about how the A in front of cos in the equation would change to 90, rather than stay 75 (in the equation for the step by step), but it would be easier to just use the Pythagorean theorem.

Step-by-step explanation:

I think we may have the same class so hopefully this helps:

1.) $a^2 = b^2 + c^2 - 2bccosA$ --> law of cosines formula.

$a^2 = 3^2 + 3^2 - 2(3)(3)cos(75)$ --> plugged in numbers; when you draw the triangle, the included angle would be A, and the opposite side would be a. B and b, and C and c are opposite each other. In this case, a is the hypotenuse.

$a^2 = 18 - 18cos75$ --> in between steps.

$a^2 = 13.341$ --> more simplifying.

$a(hypotenuse) = \sqrt{13.341} or 3.652$ --> answer

2.) This one is just an explanation: The 75 in the equation is the given angle, which is a. If this changes, it would just change in the equation too. And obviously, if it's 90 degrees, you can just use Pythagorean theorem a^2+b^2=c^2.

Good luck! :)

6 0

2 years ago

Write an equation that could be used to solve for X. A Сал 2xº tº D B

m_a_m_a [10]

Answer: Hmmmm ok look i thinks its a carrot

Step-by-step explanation:

i found a x in my carrot

5 0

2 years ago

Can someone help √64 √49 3√-27 3√8

goldfiish [28.3K]

8, 7, undefined, 6*sqrt *2

8 0

2 years ago