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3 years ago

1) Click on the name of the figure.

Mathematics

2 answers:

Rudik [331]3 years ago

8 0

Answer:

Step-by-step explanation:

Ray b

Is the answer because is if rhe vedicam

Pavlova-9 [17]3 years ago

6 0

Answer:

A;£8£(_("!£(£(£(('?_3!£+"('(3(£("('

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The scale factor from a small triangle ABC to a large triangle XYZ is 5. How many times larger will the perimeter of triangle XY

Ierofanga [76]

Answer:

Answer below :)

Step-by-step explanation:

Hi there!

Question 4 - the answer will be 5. Since the scale factor is 5, we would (hypothetically) multiply the area by 5 to get the new area of XYZ, so area XYZ is 5 times the area of ABC.

Question 5 - A.

First we multiply 45 by 12 to find the amount in inches. This is 540. Now, we divide that by 6 to get 90. This is our scale factor in inches, but the answers only show the scale in feet, so we have to convert. Divide 90 by 12 to get 7.5.

I hope this helps!

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3 years ago

Joseph is a college student at The University of Texas. He made good grades in high school and received a scholarship that pays

ki77a [65]

Answer:

Step-by-step explanation: cap

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3 years ago

Read 2 more answers

Need help asap do tonight

aalyn [17]

Answer:

answer and explanation below

Step-by-step explanation:

2.m<x=75(angle on the same line so 180-105)

m<y=105 (vertical angles of the parallelogram are equal)

m<z=75 ( vertical angle of m<x)

3.M<y = 25 ( vertical angle property)

m<z=155( on the same line)

m<z and M,x =155( vertical angles )

8 0

3 years ago

Decide whether quadrilateral ABCD with vertices 4(3,1), B(-1,-1) C(1,3), and D(5.5) is a rectangle, rhombus,square, or parallelo

Sergeeva-Olga [200]

Answer: rhombus

Step-by-step explanation:

By inspection, we can tell that there are no right angles, so we can determine it is not a square or a rectangle.

From the options, it is implied that it is a parallelogram, so to determine if it is a rhombus, we can determine if there is a pair of consecutive congruent sides.

By the distance formula,

$AB=\sqrt{(-1-3)^{2}+(-1-1)^{2}}=\sqrt{16+4}=2\sqrt{5}\\BC=\sqrt{(-1-1)^{2}+(-1-3)^{2}}=\sqrt{4+16}=2\sqrt{5}$