The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
The cost is $45.50 for the bag
Answer:
Step-by-step explanation:
No of total brown = 2 + 1 = 3 .
probability = 3 / 6
= 1 /2 .
no of males = 2
probability
= 2 / 6
= 1 /3
no of person who is both male and brown = 1
probability = 1 /6
Required probability
= probability of being brown + probability of being male - probability of being both
= 1 / 2 + 1 / 3 - 1 /6
= 4 / 6
= 2 / 3 .
You need to create a chart like the one attached and put your own values in it. The teacher wants atleast 3 inputs and outputs but 4 or 5 is better. You first need to create a rule (EX: x+1=y)
Answer:
true
Step-by-step explanation: