Question

Given a regular square pyramid with RS = 6 and PX = 4, find the following measure. PY =

Answer 1

Answer:

PY=5.

Step-by-step explanation:

In triangle PXY it is given PX=4, XY=half of RS=6÷2=3.

Two of the sides known we can find the third side using Pythagorean Theorem:

$PY^{2} =PX^{2} +XY^{2}$

Or,  $PY^{2} =4^{2}+3^{2} =16+9=25.$

Taking root of both sides PY=5.

Answer 2

Answer:

$PY=5\ units$

Step-by-step explanation:

we know that

Applying the Pythagoras Theorem

$PY^{2}=PX^{2}+XY^{2}$

In this problem we have that

$XY=RS/2=6/2=3\ units$

$PX=4\ units$

substitute

$PY^{2}=4^{2}+3^{2}$

$PY^{2}=25$

$PY=\sqrt{25}\ units$

$PY=5\ units$