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erastovalidia [21]
3 years ago
5

If the standard deviation for a Poisson distribution is known to be 3.60, the expected value of that Poisson distribution is

Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer: 12.96

Step-by-step explanation:

given data:

Poisson distributio = 3.60

solution:

The Poisson distribution expected value is same as Variance.

which is expressed as = SD^2

therefore;

the expected value

= SD^2

= 3.60^2

= 12.96

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The sale tax would be the 2% of 470
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Given parallelogram ABCD, find the lengths and angles required.
irakobra [83]

Answer:

x = 3, line AB = 17 ,  and line CD = 17

y = 10, angle A = 70, and angle D = 70

Step-by-step explanation:

well since their the same length you can put them equal to each otheir

5x + 2 = 8x - 7

subtract 5x by both sides to get --> 2 = 3x -7

add 7 to both sides and get --> 9 = 3x

divide 3 by both sides to get x = 3

now plug it back in each equation we started with and get you answers

Same steps for y but different equations

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3 years ago
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Zane calculated the missing side length of one of these triangles using the Pythagorean Theorem. Which triangle is it?
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The sum of two numbers is 17. Their difference is 3. Find the numbers.
Afina-wow [57]

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Step-by-step explanation:

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An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
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Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

H_o: \mu = 7.1

The alternative hypothesis:

H_a: \mu > 7.1

This test is right-tailed.

degree \ of \  freedom=  n - 1 \\ \\ degree \  of \  freedom  =  24 - 1 \\ \\ degree \ of \  freedom   = 23

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test t_c = 2.069

The test statistics can be computed as:

t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}

t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}

t = \dfrac{0.2}{0.204}

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Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < t_c = 2.069, then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

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