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Colt1911 [192]
3 years ago
10

To get a B in​ math, Alexandria Pappas must average 80 on five tests. Scores on the first four tests were 82​,74​,82​,and 74.Wha

t is the lowest score that she can get on the last test and still get a​ B?
Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

88 score.

Step-by-step explanation:

Given:

To get a B in​ math, Alexandria Pappas must<u> average 80</u> on five tests.

Scores on the first four tests were <em>82​, 74​, 82​, and 74.</em>

Question asked:

What is the lowest score that she can get on the last test and still get a​ B?

Solution:

Let lowest score she can get on the last test = x

As we know:

Average=\frac{Sum\ of \ observations}{Number\ of\ observations}\\ \\ 80=\frac{82+74+82+74+x}{5} \\ \\

By cross multiplication:-

80\times5=312+x \\ \\400=312+x\\Subtracting\ both\ sides\ by\ 312\\400-312=312-312+x\\88=x

Thus, she can get 88 score on the last test to get a B in​ math.

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2 years ago
Evaluate the expression using a calculator:
tester [92]

The value of the expression is 0.0265. Using exponents and power rules, the required value is calculated.

<h3>What are the exponent and power rules?</h3>

The important exponent and power rules are:

  • a⁻ⁿ = 1/aⁿ; negative exponent
  • (ab)ⁿ = aⁿ × bⁿ; power of a product rule
  • aⁿ × aˣ = aⁿ⁺ˣ; multiplication rule
  • aⁿ/aˣ = aⁿ⁻ˣ; division rule
  • a^{\frac{x}{y} } = \sqrt[y]{a^x}; fractional exponent

<h3>Calculation:</h3>

The given expression is 126^{-3/4}

Using calculator: 126^{-3/4} = 0.0265

Applying the exponent rule for evaluating the given expression:

126^{-3/4}

Applying the negative power rule;

I.e., a⁻ⁿ = 1/aⁿ

⇒ 126^{-3/4}=\frac{1}{126^{3/4}}

Applying fractional exponent rule;

I.e., a^{\frac{x}{y} } = \sqrt[y]{a^x}

⇒ \frac{1}{126^{3/4}}=\frac{1}{\sqrt[4]{126^3} }

⇒ 1/\sqrt[4]{2000376}

⇒ 1/37.6077

⇒ 0.0265

Therefore, the value of the given expression is 0.0265.

Learn more about exponent rules here:

brainly.com/question/11975096

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10 months ago
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Answer:

\dfrac{dy}{dx}=-\dfrac{2x-y-1}{2y-x-1}

Step-by-step explanation:

Differentiating, you get ...

... x·dy +y·dx +dx +dy = 2x·dx +2y·dy

Collecting terms gives ...

... dy(x +1 -2y) = dx(2x -y -1)

... dy/dx = -(2x -y -1)/(2y -x -1)

4 0
3 years ago
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