The answer for this system

Mathematics

1 answer:

Natali [406]3 years ago

8 0

Consider this option:
$\left \{ {{y=3x-4} \atop {2x+3y=21}} \right. \ =\ \textgreater \ \ \left \{ {{y=3x-4} \atop {2x+3(3x-4)=21}} \right. \ =\ \textgreater \ \ \left \{ {{y=3x-4} \atop {11x=33}} \right. \ =\ \textgreater \ \ \left \{ {{x=3} \atop {y=5}} \right.$

answer: (3;5).

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Need help on this math problem

erik [133]

Answer:

$-5, 18, \sqrt{13}$

Step-by-step explanation:

We can solve the first equation, f of -3. The value of the function f is $\frac{1+x^2}{x+1}$ , and plugging in -3 gets us $\frac{1+9}{1-3}$ , this results in 10 divided by negative 2, which is negative 5.

Now, we must solve g of negative one third. The function g is defined as $|9x-15|$ . Plugging in negative one third into the question gets us $|9(-\frac{1}{3})-15|$

9 times negative one third is -3, and -3 minus 15 is -18. The absolute value of -18 is 18.

Now, we must solve h of negative 2, and h is defined as $\sqrt{-3-8x}$ . Plugging in negative 2, we have $\sqrt{-3-8(-2)}$ . Negative 8 times negative 2 is positive 16, and 16 minus 3 is 13. The answer is the square root of 13