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sergeinik [125]
2 years ago
14

Need help on this math problem​

Mathematics
1 answer:
erik [133]2 years ago
7 0

Answer:

-5, 18, \sqrt{13}

Step-by-step explanation:

We can solve the first equation, f of -3. The value of the function f is \frac{1+x^2}{x+1}, and plugging in -3 gets us \frac{1+9}{1-3}, this results in 10 divided by negative 2, which is negative 5.

Now, we must solve g of negative one third. The function g is defined as |9x-15|. Plugging in negative one third into the question gets us |9(-\frac{1}{3})-15|

9 times negative one third is -3, and -3 minus 15 is -18. The absolute value of -18 is 18.

Now, we must solve h of negative 2, and h is defined as \sqrt{-3-8x}. Plugging in negative 2, we have \sqrt{-3-8(-2)}. Negative 8 times negative 2 is positive 16, and 16 minus 3 is 13. The answer is the square root of 13

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