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igor_vitrenko [27]
3 years ago
12

if 5 times a number is increased by 4, the result is at least 19. find the least possible number that satisfies these conditions

Mathematics
1 answer:
Brrunno [24]3 years ago
3 0
(3)   3 * 5 = 15 + 4 = 19            I believe that that is the smallest integer that would satisfy that problem. 
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One number is six more than a second number. four times the first is 10 less than 6 times the second. Find the numbers.
zavuch27 [327]

\sf{\bold{\blue{\underline{\underline{Given}}}}}

  • One number is six more than a second number.
  • four times the first is 10 less than 6 times the second.⠀⠀⠀⠀

\sf{\bold{\red{\underline{\underline{To\:Find}}}}}

  • Find the two numbers.⠀

\sf{\bold{\purple{\underline{\underline{Solution}}}}}

⠀⠀⠀⠀

In questions given,One number is six more than a second number.

if second number is a

first number is a+6.

and,

four times the first is 10 less than 6 times the second.

So,

4×(a+6)=6a-10

we have to solve this.

\bold{4\times (a+6)=6a-10   } 

\bold{4a+24=6a-10   } 

\bold{6a-4a=24+10   } 

\bold{2a=34   } 

\bold{ a=\dfrac{34}{2}  } 

\bold{ a=17  } 

we,get our second number =a=17.

So,

first number =a+6=17+6=23

5 0
3 years ago
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Answer:

6

Step-by-step explanation

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8 0
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Find the value of y.
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4 0
3 years ago
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