Answer: 0.15J
Step-by-step explanation:
Fom th question, we obtained the following information:
F = 60N
e = 5mm
We need to covert 5mm to m
1mm = 0.001m
5mm = 5 x 0.001 = 0.005m
We need to find the spring constant (K) for the spring. This is illustrated below:
K = F / e
K = 60 / 0.005 = 12000N/m
Now we can obtain the energy stored on the spring by the doing following:
Energy = 1/2 Ke^2
Energy = 1/2 x 12000 x (0.005)^2
Energy = 0.15J
