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Svetradugi [14.3K]
3 years ago
5

He scored 3 goals at Saturdays gams and scored 5 goals in yesterdays game . What is his percent of increase?

Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer: his percent of increase = 66.66%

Step-by-step explanation:

percent of increase = Increase/ Previous goal x 100

Previous goal = 3 goals

Yesterday's goal = 5 goals

Percent of increase = (5-3) / 3 x 100

=2/3 x 100

=0.6666 x 100

=66.66%

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Choose the more precise measurement. A) 32.5 lb B) 28.35 lb *​
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Step-by-step explanation:

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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
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Answer: The correct statements are

The GCF of the coefficients is correct.

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David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

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7 0
3 years ago
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Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c
slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 16.000

Sample mean, \bar{x} = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

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We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

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Thus, the value of test statistic is 1.338

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