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Tamiku [17]
3 years ago
6

What to write the word form and fraction form of 0.654

Mathematics
1 answer:
Musya8 [376]3 years ago
5 0
Word form: Six hundred fifty four thousandths
Fraction form: 654/1000= 327/500
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Simplify Expression-
kumpel [21]
In all these expressions you have a power of a power. 
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
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15) (x^3)^-5 = x^[3×(-5)] = x^(-15)

17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5

<span> 19) (c^3)^5(d^3)^0 = c^(3</span>×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15
5 0
3 years ago
Quadrilateral A’B’C’D’ is a dilation of quadrilateral ABCD about point P. Quadrilateral ABCD is shown. Side AB is labeled 5. Sid
Stolb23 [73]

Answer:  The correct option is (A) reduction.

Step-by-step explanation:  Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.

As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:

AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.

And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:

A'B'=1\dfrac{1}{4}=\dfrac{5}{4}~\textup{units},~~B'C'=1~\textup{units},~~C'D'=2\dfrac{1}{2}=\dfrac{5}{2}~\textup{units},\\\\D'A'=1\dfrac{1}{2}=\dfrac{3}{2}~\textup{units}.

We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.

Now, the scale factor is given by

S=\dfrac{\textup{length of a side of the dilated figure}}{\textup{length of the corresponding side of the original figure}}\\\\\\\Rightarrow S=\dfrac{A'B'}{AB}=\dfrac{\frac{5}{4}}{5}=\dfrac{5}{4\times5}=\dfrac{1}{4}

Since the scale factor is less than 1, so the dilation will be a reduction.

5 0
3 years ago
Read 2 more answers
14
Minchanka [31]

Answer:

B. y = -\frac{1}{5}x - 4

Step-by-step explanation:

The line has a y-intercept of -4, and if one finds the slope through the equation of \frac{y1-y2}{x1-x2}, the answer would be -\frac{1}{5}.

6 0
3 years ago
Carter lives 3 kilometers away from the school. Kyle lives 2000 meters farther away from the school then Carter does.How many me
Mars2501 [29]

Answer:

Kyle's house is 5000 m away from the school.

Step-by-step explanation:

Carter lives 3 kilometers away from the school and Kyle lives 2000 meters farther away from the school then Carter does.

Simply put, Kyle lives an extra 2000 meters plus the distance of Carter's house from the school.

So, we simply need to add the two distances given to us to the find our answer.

Let us put the distance of Carter's house in metres:

1 km = 1000 m

=> 3 km = 3 * 1000 m = 3000 m

Hence, the distance of Kyle's house from the school is:

3000 m + 2000 m = 5000 m

Kyle's house is 5000 m away from the school.

8 0
4 years ago
Which is the ratio formed when finding Tan M?
sukhopar [10]

Answer:

tanM = \frac{15}{8}

Step-by-step explanation:

tanM = \frac{opposite}{adjacent} = \frac{KL}{LM} = \frac{45}{24} = \frac{15}{8}

6 0
3 years ago
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