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satela [25.4K]
3 years ago
13

Solve x for 7× + 3 = 31​

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0
The X after the 7 is 4

X=4
Bond [772]3 years ago
7 0

Answer:

X = 4

Step-by-step explanation:

7x + 3 = 31

Step 1: Subtract 3 from both sides.

7x + 3 - 3 = 31 - 3

7x = 28

Step 2: Divide both sides by 7.

7x/7 = 28/7

Therefore, the answer is X = 4

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Answer with the explanation step by step
andrey2020 [161]

Answer:

The answer is A. \frac{3(x-21)}{(x+7)(x-7)}.

Step-by-step explanation:

To find the difference of this problem, start by simplifying the denominator, which will look like \frac{3}{x+7}-\frac{42}{(x+7)(x-7)}. Next, multiply \frac{3}{x+7} by \frac{x-7}{x-7}  to create a fraction with a common denominator in order to subtract from \frac{42}{(x+7)(x-7)}. The problem will now look like \frac{3}{x+7}*\frac{x-7}{x-7}-\frac{42}{(x+7)(x-7)}.  

Then, simplify the terms in the problem by first multiplying \frac{3}{x+7} and \frac{x-7}{x-7}, which will look like \frac{3(x-7)}{(x+7)(x-7)}-\frac{42}{(x+7)(x-7)}. The next step is to combine the numerators over the common denominator, which will look like \frac{3(x-7)-42}{(x+7)(x-7)}.

Next, simplify the numerator, and to simplify the numerator start by factoring 3 out of 3(x-7)-42, which will look like \frac{3(x-7-14)}{(x+7)(x-7)}. Then, subtract 14 from -7, which will look like \frac{3(x-21)}{(x+7)(x-7)}. The final answer will be \frac{3(x-21)}{(x+7)(x-7)}.    

4 0
3 years ago
(x-3)1/3 in its a simplest form
AleksandrR [38]

Answer:  (x-3)/3

Step-by-step explanation:

You have to multiply the fraction.

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3 years ago
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Answer:

A

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3 years ago
PLSS HELP ME WITH THIS! 15 POINTS!
victus00 [196]

Answer: Option A: 14t + 4s

Step-by-step explanation:

To find the perimeter of a shape, add up all of its side lengths. We know that the length of the rectangle is (s + 2t), and its width measures (s + 5t).

To find the perimeter, multiply the width by 2 and the length by 2 and add those expressions:


P (perimeter) = 2(s + 2t) + 2(s+5t)

P = 2s + 4t + 2s + 10t

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Hope this helps.

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