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Romashka-Z-Leto [24]
3 years ago
11

Help/answer for 13 and 14

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0
I think that both answers would have to be A.
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Name a segment skew to Wy
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3 years ago
Identify the equation of a line in slope-intercept form that is perpendicular to y = -1/3 x + 2 and passes through (2, 1).
kari74 [83]
To get your answer, you will need to find the perpendicular slope for -1/3x which is just the opposite therefore it will be 3x. Your slope is 3x as perpendicular so use this slope to do point slope. Y-1=3(x-2). Distribute y-1=3x-6. Add 1 to both sides. (-1+1) (-6+1)=-5. So your equation in slope intercept form is y=3x-5. Going through the two points.

Hope this helps!
3 0
3 years ago
What's the right answer?
Masja [62]

Given:

sinh(f(x))=1+x^2

To find:

The value of f'(x).

Solution:

Formulae used:

\dfrac{d}{dx}sinh(x)=cosh(x)

\dfrac{d}{dx}x^n=nx^{n-1}

\dfrac{d}{dx}C=0

Chain rule:

\dfrac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

Where C is an arbitrary constant.

We have,

sinh(f(x))=1+x^2

Differentiate with respect to x.

cosh(f(x))f'(x)=0+2x

f'(x)=\dfrac{2x}{cosh(f(x))}

Therefore, the required values is f'(x)=\dfrac{2x}{cosh(f(x))}.

7 0
3 years ago
Solve this pleasee!!!!!!!!!!!
Sholpan [36]

Answer:

1) Solution (2,-3)

2) Solution (-1, -\frac{3}{2})

3) Solution (\mathbf{-\frac{1}{2},-\frac{5}{2}})

Step-by-step explanation:

We need to solve equations using elimination

1) 2x+2y=-2\\3x-2y=12

Let:

2x+2y=-2--eq(1)\\3x-2y=12--eq(2)

Adding both equations:

2x+2y=-2\\3x-2y=12\\--------\\5x=10\\x=\frac{10}{5}\\x=2

We get value of x = 2

Now, put value of x into equation 1 to find value of y

2x+2y=-2\\Put\:x=2\\2(2)+2y=-2\\4+2y=-2\\2y=-2-4\\2y=-6\\y=-6/2\\y=-3

So, we get y = -3

Solution (2,-3)

2) 4x-2y=-1\\-4x+4y=-2

Let:

4x-2y=-1--eq(1)\\-4x+4y=-2--eq(2)

Adding both equations

4x-2y=-1\\-4x+4y=-2\\------\\2y=-3\\y=\frac{-3}{2}

We get: y= -3/2

Now find value of x by putting value of y in eq(1)

4x-2y=-1\\Put\:y=\frac{-3}{2}\\4x-2( \frac{-3}{2})=-1\\4x+3=-1\\4x=-1-3\\4x=-4\\x=\frac{-4}{4}\\x=-1

We get x = -1

Solution (-1, -\frac{3}{2})

3) x-y=2\\x+y=-3

let:

x-y=2--eq(1)\\x+y=-3--eq(2)

Add both equations:

x-y=2\\x+y=-3\\-----\\2x=-1\\x=-\frac{1}{2}

We get x = -1/2

Now, put value of x in equation 2

x+y=-3\\-\frac{1}{2}+y=-3\\y=-3+ \frac{1}{2}\\y=\frac{-6+1}{2}\\y=\frac{-5}{2}

We get y = -5/2

Solution (\mathbf{-\frac{1}{2},-\frac{5}{2}})

7 0
3 years ago
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