A and B i believe, hope it helped.
Polysaccharides like Cellulose form insoluble micro-fibrils making it resistant to degradation and enzymatic activity.
<u>EXPLANATION: </u>
- Polysaccharides components in general broken down monosaccharides and they are very little enough to be absorbed by the body.
- But the polysaccharide like cellulose cannot be absorbed by our body.
- Cellulose is made up of simple polymers that form insoluble micro-fibrils results in resistant to degradation and enzymatic activity.
- Also, molecules of each micro-fibril are so tightly packed structure and prevent the penetration of enzymes.
- Thus, cellulose degradation requires a complex enzyme and cellulose.
Answer:
Option (b).
Explanation:
The frequency of alleles K and k in population are 0.6 and 0.4. The inbreeding coefficient is 0.3.
The heterozygote frequency can be calculated by the formula:
F = 
Here, K = 0.6, k= 0.4, F = 0.3 and H = approximate genotypic frequency of heterozygote Kk.
Put the values in the above formula
0.3 = 
H = 0.36 ≈ 0.34.
Thus, the approximate genotypic frequency of the heterozygote Kk is 0.34.
Hence, the correct answer is option (b).