Answer:
1033.2 g or 1.033 kg
Step-by-step explanation:
(620/12)(20) = 1033.2 g
Answer:
At least 6907 people.
Step-by-step explanation:
Population std deviation = sigma= 10.6
Since population std deviation is known, we can use normal probability table to get sample size from confidence interval.
The sample mean weight loss is within 0.25 lb of the true population mean.
Hence margin of error < 0.25
Margin of error = z critical (std dev/n) where n = sample size
Z critical for 95% = 1.96
Hence 0.25 >1.96(10.6)/sq rt n
Simplify to get
sq rt n > 1.96(10.6)/0.25 = 83.104
Square both the sides to get
n > 83.104 square = 6906.27
i.e. sample size should be atleast 6907.
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
c) they are screw lines
Step-by-step explanation:
A and B will intersect but never create a 90 degree angle. It comes at and angle smaller
Population of moose in the national park = 240
percentage increase in the population of moose in the national park after a year = 25%
Then
Amount of increase in the population
Of moose in the national park in a year = (25/100) * 240
= 240/4
= 60
So
The number of moose present after 1 year
in the national park = 240 + 60
= 300
So from the above deduction we can easily conclude that the number of moose in the national park after a year is 300.
