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Ilia_Sergeevich [38]
3 years ago
14

Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.

Mathematics
1 answer:
evablogger [386]3 years ago
4 0

Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) (5^2)(5^3)

As we know that

a^m\times a^n=a^{m+n}

So, it becomes,

5^2\times 5^3=5^{2+3}=5^6=15625

(b) (5^2)(5^{-3})

So, it becomes,

5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2

(c) (5^2)^2

As we know that

(a^m)^n=a^{mn}

So, it becomes,

5^{2\times 2}=5^4=625

(d) 5^{-3}

a^{-m}=\dfrac{1}{a^m}\\\\5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}=0.008

Hence, a) 15625, b) 0.2, c) 625, d) 0.008.

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3 years ago
The five-number summary of the ages of passengers on a cruise ship is listed below. Min 1 Q1 20Median 29 Q3 38Max 80 Consider th
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Answer: b. Only statement (ii) is correct.

Step-by-step explanation:

The given five-number summary of the ages of passengers on a cruise ship is listed below.

Min 1    Q_1 20     Median 29     Q_3 38         Max 80

Inter-quartile range = IQR=Q_3-Q_1=38-20=18

  • According to the 1.5(IQR) criterion for outliers : An data value is an outlier if it lies below Q_1 - 1.5(IQR) or  above Q_3 + 1.5(IQR).

Here , Q_1 - 1.5(IQR) =20-1.5(18)=-7

Q_3 + 1.5(IQR)=38+1.5(18)=65

Since the minimum value> Q_1 - 1.5(IQR) ( ∵ 1 > -7)

It means there is no value below Q_1 - 1.5(IQR)  , so there is no low -outlier.

⇒ Statement (i) "here is at least one passenger whose age is a low outlier. " is false.

But the maximum value > Q_3 + 1.5(IQR) (∵  85 > 65)

It means there are values above Q_3 + 1.5(IQR).

⇒Statement (ii) "There is at least one passenger whose age is a high outlier" is true.

Hence, the correct answer is b. Only statement (ii) is correct.

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Answer:


Step-by-step explanation:


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Which line is parallel to a line that has a slope of 3 and a y-intercept at (0, 0)?
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Answer:

HJ

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

so

The slope of the line that is parallel to a line that has a slope of 3 is equal to 3

Verify the slope of the blue and red line , because their slopes are positive

<em>Blue line</em>

we have

C(-3,0),D(3,2)

The slope m is equal to

m=(2-0)/(3+3)

m=2/6

m=1/3

<em>Red line</em>

we have

H(-1,-4),J(1,2)

The slope m is equal to

m=(2+4)/(1+1)

m=6/2

m=3

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The answer is the red line HJ

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A fraction bar. The top bar is labeled 1. 4 bars underneath the bar are labeled one-fourth. 5 bars underneath the 4 bars are lab
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Answer:

Step-by-step explanation:

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