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3 years ago

Someone please help me with this math question!

Mathematics

2 answers:

stepladder [879]3 years ago

8 0

$1.25x + 2.5 \ \textless \ 2.75x - 6.5 \\ \\ 2.5 \ \textless \ 2.75x - 6.5 - 1.25x \ / \ subtract \ 1.25x \ both \ sides \\ \\ 2.5 \ \textless \ 1.5x - 6.5 \ / \ simplify \\ \\ 2.5 + 6.5 \ \textless \ 1.5x \ / \ add \ 6.5 \ both \ sides \\ \\ 9 \ \textless \ 1.5x \ / \ simplify \\ \\ 6 \ \textless \ x \ / \ divide \ both \ sides \ 1.5 \\ \\ x \ \textgreater \ 6 \ / \ change \ sides \\ \\ Answer: x \ \textgreater \ 6 (A)$

Gnom [1K]3 years ago

3 0

1.25x+2.5 <2.75x-6.5 =>
=> 2.75x-1.25x > 2.5+6.5 =>
=> 1.5x > 9 =>
=> x > 6
So A is the correct answer~~
Hope that helps! :)

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After a storm, 135 trees out of 180 were left standing. What is the percentage loss of the number of trees?

beks73 [17]

Answer:

Percentage loss of the number of trees is $25\%$ .

Step-by-step explanation:

Given: After a storm, $135$ trees out of $180$ were left standing.

To find: What is the percentage loss of the number of trees?

Solution:

We have,

Total number of trees $=180$

Number of trees left standing $=135$

Therefore, loss of trees $=180-135=45$

We now that $\text {Loss\%}=\frac{\text{Number of trees left}}{\text{Total number of trees}}\times 100 \%$

$\implies \text {Loss\%}=\frac{45}{180}\times 100 \%$

$\implies \text {Loss\%}=\frac{450}{18} \%$

$\implies \text {Loss\%}=25 \%$

Hence, the percentage loss of the number of trees is $25\%$ .

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3 years ago

Solve the following probability problem. Give the answer in a

Lesechka [4]

Step-by-step explanation:

The probability of not selecting green or yellow marble is equal to the probability of selecting red and blue marble

n(S) =17

n(A)=5 (red)

n(B)=6 (blue)

answer is 5+6/17

=11/17

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2 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

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2 years ago

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pshichka [43]

Answer:

the sum of 2 consecutive even integers is 66.

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