1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuliya22 [10]
3 years ago
5

Select the histogram that represents the given test scores

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0
23 I think not real sure
You might be interested in
Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th
amm1812
(5,22.45),(7,25.45)
slope = (25.45 - 22.45) / (7 - 5) = 3/2 or 1.5

y = mx + b
slope(m) = 1.5
use either of ur points...(5,22.45)...x = 5 and y = 22.45
now sub and find b
22.45 = 1.5(5) + b
22.45 = 7.5 + b
22.45 - 7.5 = b
14.95 = b

so ur equation is : y = 1.5x + 14.95.......this means that each quart of oil costs $ 1.50 and the labor fee costs $ 14.95
3 0
3 years ago
The graph below shows the relationship between test grades and shoe sizes of the students in Dexter's class.
FrozenT [24]
Yeah that is correct so yeah you are right I don’t know any more information that I could give you but I’m pretty sure you just said it right so yeah
4 0
2 years ago
Read 2 more answers
Calculate m∠ABC and m∠CBD, what is the value of x?<br><br> Enter your answer in the box.
QveST [7]
X is twenty

2x+6x+20=180
8x=160
X=20
8 0
2 years ago
Read 2 more answers
Choose the solution to this inequality. 43&lt;−83y
inn [45]
Maybe A
I don’t really know
4 0
3 years ago
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa
gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = \dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}

The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

The probability of two 1's and two 4's in both die = \dfrac{5}{216}

By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

8 0
3 years ago
Other questions:
  • Jodie bought some shirts for $6 each. Marge bought some shirts for $8 each. The girls spent the same amount of money on shirts.
    12·2 answers
  • 14pqr+35pqr factorise
    13·1 answer
  • Molly is on a game show. To win $1,000,000, she must answer this question: What key features are necessary—and how are the featu
    9·1 answer
  • Which statement is an example of the transitive property of congruence?
    8·1 answer
  • PLS HELP ASAP
    9·1 answer
  • How many outcomes are there in the sample space for tossing 2 coins?
    8·2 answers
  • Which set of Ordered pairs represent y as a function of x
    6·1 answer
  • HELP Solve: p – 23 = 23 A. p = 24 B. p = 46 C. p = 52 D. p = 44
    9·1 answer
  • If the outlier is removed, which measure will not change?<br><br> mean<br> median<br> mode<br> range
    5·1 answer
  • Not sure how to do this, could use some help. : )
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!