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Paraphin [41]
3 years ago
12

Determina la masa molar y el volumen que ocupa la siguiente sustancia CO2, si su masa es de 28 gr. *

Mathematics
1 answer:
balandron [24]3 years ago
7 0

Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3

Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

Carbono: tiene una masa molar de 12 g/mol

Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

masa molar = 12g/mol + 2*16g/mol = 44 g/mol

Es decir, un mol de CO₂, pesa 44 gramos.

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The diameter of a circle is 34 yards. What is the circle's area? Use 3.14 for ​.
barxatty [35]

Answer:

907.46 mm2

Step-by-step explanation:

Area of circle = (¶d^2)/4

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8 0
2 years ago
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How to factor y^3 +2y^2 + 2y + 1
cupoosta [38]

Answer:

Step-by-step explanation:

P(y) = y³ + 2y² + 2y + 1  

P(-1) = (-1)³ + 2*(-1)² + 2*(-1) + 1

      = -1 + 2 - 2 + 1

      = 0

As, P(-1) = 0, (y + 1) is a factor.

  Use synthetic division or remainder theorem.

-1        1          2           2           1

       <u>    0        -1            -1         -1        </u>

           1          1            1            0

quotient = y² + y + 1

y³ + 2y² + 2y + 1  = ( y + 1) (y² + y + 1)

 

4 0
3 years ago
What’s the pattern of -1, -8, -27, and -64
AURORKA [14]

Hello from MrBillDoesMath!

Answer:

a(n) = (-n)^3  where n = 1,2,3,...


Discussion:

The pattern  1,8,27, 64... is immediately recognizable as the the cube of the positive integers. But this question has a minus sign appearing before  each entry, suggesting we try this:


 - 1  =  (-1)^3

 -8  = (-2)^3

-27  = (-3)^3

-64  = (-4)^3

That's what the problem statement asked for . The answer is equivalently

-1 * (n^3)


Thank you,

MrB

6 0
3 years ago
A triangle can be formed with side lengths 2in, 3in and 6 in?<br>true or false?​
Aleks04 [339]

Answer:

No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.

For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.

2

in.

+

3

in.

=

5

in.

5

in.

<

6

in.

For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:

3 + 4 = 7 which is greater than 5

3 + 5 = 8 which is greater than 4

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Step-by-step explanation:

4 0
3 years ago
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