That which is NOT part of the respiratory membrane of the lungs is:
- A thin layer of ciliated epithelial cells
<h3>What is the respiratory membrane?</h3>
The respiratory membrane is the surface of the lungs where there is an exchange of gases. There are many parts that make up the respiratory membrane of the lungs.
Some of these are; the respiratory mucosa, the adventitia, and the submucosa. The thin layer of ciliated epithelial cells is not a part of the respiratory membrane but is a hair-like structure that helps to remove unwanted substances from the body.
So the correct answer is: a thin layer of ciliated epithelial cells.
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Answer:
$10.50
Explanation:
all you have to do is 3.50 x 3
The most widely used source of short-term funding that Mr. Boyd (and other small business owners) would use to operate their business is trade credit.
<h3>What is Trade Credit?</h3>
This refers to the purchase financing where a person is allowed to collect goods and pay for them at a later date.
Hence, we can see that short term fundings are used to help startups and other businesses to stay afloat and the type of funding used by Mr. Boyd is trade credit.
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The oxidation number if eah of the elements is as follows;
- Oxidation number of Mn is + 7 on the right hand side and +4 on the right hand side
- Oxidation number if hydrogen is +1 on both sides
- The oxidation number of oxygen is -2 on both sides
- The oxidation number of sulfur is -2 on the lefthand side and zero on the right hand side.
<h3>What is a redox reaction?</h3>
A redox reaction is one in which there is a change in the oxidation number of the reactants from left to right.
Let us now consider the oxidation number of each element from left to right;
- Oxidation number of Mn is + 7 on the right hand side and +4 on the right hand side
- Oxidation number if hydrogen is +1 on both sides
- The oxidation number of oxygen is -2 on both sides
- The oxidation number of sulfur is -2 on the lefthand side and zero on the right hand side.
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Answer:
2440.24 J
Explanation:
Moment of inertia, I1 = 5 kg m^2
frequency, f1 = 3 rps
ω1 = 2 x π x f1 = 2 x π x 3 = 6 π rad/s
Moment of inertia, I2 = 2 kg m^2
Let the new frequency is f2.
ω2 = 2 x π x f2
here no external torque is applied, so the angular momentum remains constant.
I1 x ω1 = I2 x ω2
5 x 6 π = 2 x 2 x π x f2
f2 = 7.5 rps
ω2 = 2 x π x 7.5 = 15 π
Initial kinetic energy, K1 = 1/2 x I1 x ω1^2 = 0.5 x 5 x (6 π)² = 887.36 J
Final kinetic energy, K2 = 1/2 x I2 x ω2^2 = 0.5 x 3 x (15 π)² = 3327.6 J
Work done, W = Change in kinetic energy = 3327.6 - 887.36 = 2440.24 J
