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3 years ago

What is the standard form of 1.46e-6?

2 answers:

7 0

The "e" represents how many zeroes there are (or in other terms, how many decimal places we shift, either to the left or to the right)...since it's -6, we move the decimal place six places to the left (since it's negative).

<span>1.46 e-6

</span>So the answer is

= 0.00000146

VARVARA [1.3K]3 years ago

6 0

The standard form is 0.00000146

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Solve the system of equations by graphing.

umka2103 [35]

ANSWER

The solution set is (4,6)

EXPLANATION

The first equation is

$y = - 3x + 18$

The intercepts are:

(0,18) and (6,0).

We plot the intercepts and draw a straight line through them.

The second equation is,

$3x - 2y = 0$
This equation also passes through,

(0,0) and (1,1.5).

We plot this point too and draw a straight line through them.

The two straight lines intersect at (4,6).

See graph.

Hence the solution set is (4,6).

4 0

3 years ago

Read 2 more answers

IWhat is the slope of the line whose equation is y-4=5/2(x-2)?

bulgar [2K]

Answer:

5/2

Step-by-step explanation:

You slope is always <em>mx</em>

In point-slope form, your mx is just in factored form. All you need to do is distribute to find m.

6 0

3 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$