Answer:
Step-by-step explanation:
Step-by-step explanation:
By taking ( x = 18°)
<u>L.H.S</u>
cos(3x)=sin(2x)
cos(3x) = cos( 3X18°)= cos (54°)
= cos[ 90° - (2x18°)] ∵[ 90°- (2x18°) = 54°]
= ∴ sin ( 2x18°)
As (x = 18°)
= sin (2x) = R.H.S
ANSWER
Frequency=2
Midline =3
Amplitude =5
Period =π
EXPLANATION
We have:

The given function is of the form;

where
a=|5| =5 is the amplitude
and b=2 is the frequency.
and 2π/b=2π/2=π
The range of the given function is
8≤y≤-2
The midline is

Answer:
See attached for a graph
Step-by-step explanation:
We're going to plot sea level as y=0 and a depth of 8 meters as y=-8.
The problem statement tells you the initial point (x=0) is at normal ocean depth (y=-8), so the first point you put into your sine tool is ...
(x, y) = (0, -8)
The buoy takes 16 seconds to go from a high point to a low point, so the time to the first high point is half that, or x=8 seconds. That high point is 5 meters above its average depth, so is at y=-3.
The second point you will put into your sine tool is ...
(x, y) = (8, -3)
The range of a relation is the possible output values, the y-values.