Ask question

Ask question

All categories

3 years ago

13

Describe how the value of n affects the shape of the binomial probability histogram. choose the correct answer below.

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

Answer: C

The value n represents the number of trials in the binomial distribution. As you increase the number of n, you are increasing the number of bars that would be in your distribution. In effect, you are making it look more and more like a simple bell curve as you increase the number of bars, because they are getting closer together.

You might be interested in

Graph the linear function using the slope and y-intercept.<br> y=1/3x+3

hammer [34]

Answer:

Graphed this on desmos, hope it helped!!

Step-by-step explanation:

8 0

2 years ago

The use of the internet is constantly growing. How many randomly selected adults must be surveyed to estimate the percentage of

Alika [10]

Out of those 2 answers I believe your answer would be B only because 81% of Americans in the us have a phone and 35% of people in the us check there phone more than 50 times per day

7 0

3 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

suppose you choose a marble from a bag containing 3 red marbles, 3 white marbles, and 5 blue marbles. You return the first marbl

Marta_Voda [28]

Answer:

15/121 is the answer.

8 0

3 years ago

Carl is boarding a plane. He has 222 checked bags of equal weight and a backpack that weighs 4 Write an equation to determine th

dangina [55]

Answer: 2w + 4 = 35

Step-by-step explanation:

Carl's two checked bags and his one backpack together weigh 35kg.

Carl's two checked bags have equal weight so both their weight can be denoted as 2w.

Equation is;

2w + 4 = 35

If you were to solve;

2w + 4 = 35

2w = 35 - 4

w = 31/2

w = 15.5kg

4 0

3 years ago