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vivado [14]
3 years ago
10

A 20-gallon salt-water solution contains 15% pure salt. How much pure water should be added to it to produce a 10% solution?

Mathematics
1 answer:
Elanso [62]3 years ago
3 0

15% of 20 gal = 0.15 * 20 gal = 3 gal, so the solution contains 3 gal of salt.

If we add <em>x</em> gal of water to the solution, we end up with (20 + <em>x</em>) gal of solution. We want the new mixture to have a concentration of 10%, or

10% of (20 + <em>x</em>) gal = 0.1 * (20 + <em>x</em>) gal = 2 + 0.1<em>x</em> gal

of salt.

The amount of salt in the tank hasn't changed. Solve for <em>x </em>:

2 + 0.1<em>x</em> = 3

0.1<em>x</em> = 1

<em>x</em> = 10 gal

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