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nadya68 [22]
3 years ago
8

Which set of numbers is arranged from least to greatest?

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

The correct answer is option B

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Factor p^2-q^2-2p+2q
Grace [21]
Not sure of the answer but i know what factors
p ^2 - 2p

p (p-2)

-q^2 +2q

-q (q-2)

so maybe (p-q) (p-2) (q-2)
6 0
2 years ago
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Find the answer<br> -4(41)<br> 4(-41)<br> -4(-41)
Anna71 [15]

Answer:

-4(-41)

Step-by-step explanation:

3 0
2 years ago
Simplify 2/9 + 1/3 + 2/3=
Maurinko [17]
2/9 + 1/3 + 2/3
2/9 + 3/9 + 6/9
(2 + 3 + 6) /9
11/9
7 0
3 years ago
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A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
Solve the inequality<br> -2≥4p+6+4
Alchen [17]

Hi there


-2 ≥ 4p + 6 + 4

-2 ≥ 4p + 10

4p +10 ≤ -2

Now subtract 10 form both sides

4p + 10 - 10 ≤ -2 - 10

4p ≤ -12

Divide by 4

4p/4 ≤ -12/4

p ≤ -3


I hope that's help:)

3 0
3 years ago
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