Answer: 16 square units
Step-by-step explanation:
let the vertex in quadrant I be (x,y)
then the vertex in quadratnt II is (-x,y)
base of the rectangle = 2x
height of the rectangle = y
Area = xy
= x(12 - x²)
= -x³ + 12x
d(area)/dx = 3x² - 12 = 0 for a maximum of area
3x² = 12
x² = 4
x = ±2
y = 12-4 = 8
So, the largest area = 2 x 8 = 16 square units
Answer:
Step-by-step explanation:
simplify
to
then
-0.05 × 120 = -6
then we have our answer
-6√2
Answer:A= 1,2 B=1,2 C=-9,10
Step-by-step explanation:
For A=
To find A', reflect the triangle exactly over the y-axis. That will put your A' at (1,2)
For B=
translate the triangle clockwise around the origin, (0,0), to put B' at (1,2)
For C= Translate point C to the left 4, and up 2, so the answer is (-9,10)
