We have to determine the equation of the line passing through the point (2,-5) and parallel to the line 
When two lines are parallel, then the slopes of the two lines are equal.
Equation of line with point 
and slope 'm' is given by:
Since, we have to determine the equation of a line with point (2,-5).
So, the equation of the line is : 
Since, the line is parallel to the line 
So, 
So, slope of the line 'm' is 
.
Therefore, the equation of the line is:
Therefore, is the required equation of the line.
Answer:
Explanation given below.
Step-by-step explanation:
The first step is to put the parabola in the form 
, which is the <em>standard form of a parabola</em>
<em />
<u>Note:</u> a is the coefficient before x^2 term, b is the coefficient before x term, and c is the independent constant term
The axis of symmetry divides the parabola symmetrically. The axis of symmetry has the equation 
Where <em><u>a and b are the respective values shown above</u></em>
<em><u /></em>
So, that is how you get the axis of symmetry of any parabola.
Answer:
7 square units
Step-by-step explanation:
As with many geometry problems, there are several ways you can work this.
Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.
The applicable formulas are ...
area of a trapezoid: A = (1/2)(b1 +b2)h
area of a triangle: A = (1/2)bh
So, our areas are ...
AQRS = AWSQE - AWSR - AEQR
= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)
Factoring out 1/2, we have ...
= (1/2)((2+5)·4 -2·2 -5·2)
= (1/2)(28 -4 -10) = 7 . . . . square units
A=1/2*b*h
A=1/2*3*11
A=1/2*33
A=16.5
I hope this helps!
~kaikers
