Let the second car meets the first car after n hours.
Second car starts with 8km/h, After succeeding hours his speed increases by 0.5 km.
So, Distance travelled by second car = 8 + 8.5 + 9
..... 8+(n-1) 0.5.....(1)
eqn. (1) sum of n terms Of A.P with first term 8
and common difference 0.5.
Sum of all the terms in equation 1 is also equals to the distance travelled by the first car for n hours, i.e. 10n km .
Now, we have (n/2) {16+(n-1) 0.5} = 10n........(2)
From equation (2) we get, n= 9
Hence, Both the cars will meet after 9 hours.
Hope it helps!
$60 - $10 = $50
$50 / 20 = $2.5 ea.
Answer:
the answer is b. the segment has a length of 8 units vertical.
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
It's the first number on the graph that you can go into.
