Answer:
45 different ways to fill the positions.
Step-by-step explanation:
Consider the provided information.
Management selection. A corporation plans to fill 2 different positions for vice-president, V₁ and Upper V₂, from administrative officers in 2 of its manufacturing plants. Plant A has 9 officers and plant B has 5.
We need to find the probability that 2 positions be filled if the Upper V₁ position is to be filled from plant A and the Upper V₂, position from plant B?
To fill the post of V₁ from plant A, which has 9 officers, we have 9 ways.
To fill the post of V₂ from plant B, which has 5 officers, we have 5 ways.
Therefore, the total number of ways are:
Hence, 45 different ways to fill the positions.
Answer:
27
Step-by-step explanation:
6f - 3g + 4h
6(2) - 3(-1) + 4(3)
12 + 3 + 12
27
9514 1404 393
Answer:
C. The zeros are -1 and 5/2, because f(x) = (x + 1)(2x-5).
Step-by-step explanation:
The zeros of the function are the values that make the factors zero. The factors need to multiply out to give the original standard-form equation.
The sign of the constant (-5) tells you the product of the constants in the factors must be -5. That is only true for choices B and C.
Additionally, the x-term needs to match the result of multiplying out the factors.
B. (x -1)(2x +5) = 2x^2 +3x -5 . . . . . . . . . wrong x-term (not -3x)
C. (x +1)(2x -5) = 2x^2 -3x -5 . . . . . . . . . matches the given f(x)
The factors of C are zero when x=-1, x=5/2.
Answer:
The answer would be c
Step-by-step explanation: