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Fiesta28 [93]
3 years ago
8

PLEASE HELP ME WITH THIS QUESTION ^^

Mathematics
1 answer:
AURORKA [14]3 years ago
4 0
I’m sorry I don’t get that whole situation
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What are letters A, B, and C?
uranmaximum [27]

Answer:

a. (3-7x) + (3-7x) + (3-7x) + (3-7x)

b. 4(3-7x)

c. 12 - 28x

Step-by-step explanation:

To find the perimeter of a square, you need to add up all the sides

a. Since a square has all equal sides you will need to write the expression four times: (3-7x) + (3-7x) + (3-7x) + (3-7x) = perimeter

b. Expressing this as a product, we can condense the formula to 4 multiplied by the expression since it is written four times: 4(3-7x) = perimeter

c. Using the distributive property, we can write the product 4(3-7x) from b. as: (4)(3) + (4)(-7x) = 12 + (-28x) = 12 - 28x = perimeter

6 0
3 years ago
Help pleaseeeeeeeeeeeeeeeeeeee
Jlenok [28]

Answer:

3.55 x t = 28.40 or 28.40/t = 3.55

Step-by-step explanation:

8 0
3 years ago
Find the distance between each pair of points.
antoniya [11.8K]

Answer:

Between each pair of points are coordinates K(x1,y1) F(x2, y2)

Distance KF =sqrt( (x2 - x1) ² + (y2 - y1) ²)

Step-by-step explanation:

4 0
3 years ago
The equation W= 4d+ 5110 represents the daily weight in pounds of a Tyrannosaurus Rex d days after its 14th birthday how much wo
umka21 [38]
Substitute "d" = 2, 3.5 and 5 in the given equation and solve to get the "W" values for the respective days. Then plot the graph using days "d" in the "x" axis and weight "w" in the "y" axis the graph will be most definitely "Linear".
5 0
3 years ago
A bridge over a gorge is supported by an arch in the shape of a semi-ellipse. The length of the bridge is 400 ft. and the maximu
Hitman42 [59]

Answer:

The height of the arch 50ft from the center is 97ft

Step-by-step explanation:

A bridge over a gorge is supported by an arch in the shape of a semi-ellipse

The length of the bridge is 400 ft. and the maximum height is 100 ft

so, a=200ft

b=100ft

(a)

we can draw picture


(b)

now, we can use equation of ellipse formula

\frac{x^2}{a^2}+ \frac{y^2}{b^2}=1

now, we can plug

a=200

b=100

\frac{x^2}{200^2}+ \frac{y^2}{100^2}=1

we can plug x=50 and find y

\frac{50^2}{200^2}+ \frac{y^2}{100^2}=1

y=25\sqrt{15}

y=97ft


6 0
3 years ago
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