Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
Answer:
11.8845
Step-by-step explanation:
11.8845 to the up and down answer it will be down
Answer:X= 41
Step-by-step explanation:
Answer:
5c + 1.3d - 6.3
Step-by-step explanation:
Hope this helps.
