General equation of parabola: y-k = a(x-h)^2
Here the vertex is at (0,0), so we have y-0 = a(x-0)^2, or y = ax^2
All we have to do now is to find the value of the coefficient a.
(1,2) is on the curve. Therefore, 2 = a(1)^2, or 2 = a(1), or a = 2.
The equation of this parabola is y = 2x^2.
15 / 40 = .375
total # total #
of girls of students
.375 = 37.5%
15/40 as a fraction ---> simplify ---> 3/8
Answer:
I think it's 4y
Step-by-step explanation:
I think it's 4y is because if y = 0 they all work but 4y which is 0 while all the others are 4
in parallelogram EFGH
the mid point of diagonal EG is
(-3-5)/2,(1+5)/2=(-4,3)
similarly the midpoint of diagonal FH is
(0-2)/2,(2+6)/2=(-1,4)
Answer:
Just by simply adding the two quantities you can get the net change. $67.12 +(addition sign because we want the net change) $2.56= $69.68. The last number is the net change!
Step-by-step explanation:
