Find the prime factorization of 2001

Mathematics

1 answer:

marusya05 [52]3 years ago

4 0

Rime factorization of 2001:

By prime factorization of 2001 we follow 5 simple steps:
1. We write number 2001 above a 2-column table
2. We divide 2001 by the smallest possible prime factor
3. We write down on the left side of the table the prime factor and next number to factorize on the ride side
4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)
5. We continue until we reach 1 on the ride side of the table

2001prime factorsnumber to factorize36672329291

Prime factorization of 2001 = 1×3×23×29= 1 × 3 × 23 × 29

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A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

likoan [24]

72 is the minimum grade he must get on the last test in order to have an average of 77.

Step-by-step explanation:

The grades of a student are given 72,91,78,72 and the grade of his last test is not given.

You have to find the minimum grade the student shall get, so that the student average must be 77.
The four grades are already given. Therefore, we need to find only the fifth grade.

The term average is defined as the sum of all the data in a set divided by the number of data in a set.

Here, the number of data is 5. (Because the students has 4 grades plus one grade for his last test).

The average he should get is 77.

Average = Sum of all grades / number of grades

Let, 'x' be the grade of the last test.

⇒ 77 = (72+91+78+72+x) / 5

⇒ 77 = (313+x) / 5

⇒ 385 = 313 + x

⇒ x = 385 - 313

⇒ x = 72

The minimum grade he must get on the last test is 72.

5 0